Answer:
Step-by-step explanation:
Perimeter of a rectangle is expressed as (2 length + 2 width) = 2(L + W)
A) The length of rectangle A is y + 1
The width of rectangle A is x
Perimeter of rectangle A = 2(y + 1 + x) = 2y + 2 + 2x
= 2x + 2y + 2
The length of rectangle B is 2x - 2y
The width of rectangle B is x + 1
Perimeter of rectangle B = 2(2x - 2y+ x + 1) = 4x - 4y + 2x + 2) = 4x + 2x - 4y + 2
= 6x - 4y + 2
The length of rectangle C is 3x + 3y
The width of rectangle C is 2x - 3
Perimeter of rectangle C = 2(3x + 3y + 2x - 3) = 6x + 6y + 4x - 6) =
(6x + 6y + 4x - 6)
= 10x + 6y - 6
B) The combined perimeters will be the sum if perimeter of rectangle A, perimeter of rectangle B and perimeter of rectangle C. It becomes
2x + 2y + 2 + 6x - 4y + 2 + 10x + 6y - 6
Collecting like terms
2x + 6x + 10x + 2y + 6y - 4y + 2 + 2 - 6
The combined perimeter = 18x + 4y - 2
Answer: 12/4
Step-by-step explanation: whole number = 3. given denominator = 4. 4/4 = 1. 1 times 3 = 3. 4 plus 4 plus 4 = 12. therefore answer is 12/4
Answer: y = 6 mi. .
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Explanation:
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Area of a triangle = (½) * (base) * (height) ;
or, A = (½) * b * h ; or, A = b*h / 2 ;
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Given: A = 24.3 mi ² ;
b = 8.1 mi
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Find the height, "h" ; (in units of "miles", or , "mi" ).
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Plug in the known values into the formula:
24.3 mi ² = (½) * (8.1 mi) *(h) ;
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Solve for "h" (height) ;
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(½) * (8.1 mi) = 4.05 mi ;
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Rewrite:
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24.3 mi² = (4.05 mi) *(h) ; Solve for "h" ;
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Divide each side of the equation by "(4.05 mi)" ; to isolate "h" on one side of the equation ; and to solve for "h" ;
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24.3 mi² / 4.05 mi = (4.05 mi) *(h) / 4.05 mi ;
→ 6 mi = h ; ↔ h = 6 mi.
→ h = y = 6 mi.
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Answer:
it's 48 promise because if you do 6x8 you get =48
Answer: (2*3) = 6
(2*9) = 18 6+ 18 = 24
(3+9) = 12
Step-by-step explanation:
So whats missing is times 2 on the right side next to (3+9) *2
(2×3)+(2×9)=. (3+9)*2