Alana is skateboarding at 19 km/h and throws a tennis ball at 11 km/h to her friend Oliver who is behind her leaning against a w
1 answer:
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Answer:
The frequency of the second harmonic () is 11.97 Hz.
Explanation:
Given;
mass of the string, m = 25 g = 0.025kg
tension on the string, T = 43 N
length of the string, L = 12 m
The speed of wave on the string is given as;
where;
μ is mass per unit length = 0.025 / 12 = 0.002083 kg/m
The wavelength of the first harmonic wave is given as;
The frequency of the first harmonic is given as;
The wavelength of the second harmonic wave is given as;
The frequency of the second harmonic is given as;
Therefore, the frequency of the second harmonic () is 11.97 Hz.
To solve this problem it is necessary to apply the concepts related to the orbital velocity of a satellite on earth.
This concept is expressed in the equation,
Where,
G = Universal Gravitational constant
Mass of the Earth
Therefore the ratio of the velocity from two satellites is,
The ratio between the two satellites is the same, then
Therefore the correct option is B.