Answer:
a) 25.5 µH
b) 22.95 mV
Explanation:
Induced emf in a inductor is given by
E = L * di/dt, where
E is the voltage of the circuit
L is the inductance of the circuit
di/dt if the rate of inductance
A
So we have
0.0037 = L * 145
L = 0.0037 / 145
L = 0.0000255
L = 25.5 µH
B
i(t) = 225t²
Recall that
E = L * di/dt, so that
E = 25.5 µH * |225t²|
Differentiating with respect to t, we have
E = 25.5 * 2 * 225t
E = 25.5 * 450t
Solving for t = 2,we get
E = 25.5 * 450(2)
E = 25.5 * 900
E = 22950 µV or
E = 22.95 mV
1. make good decisions
2. explosive
3. favorable
answered these on edge. also, you marked this as physics even though its english. might wanna watch out for that lol, so youll get a quicker answer
Answer:
111.5 m
Explanation:
Given that You are driving to the grocery store at 14 m/s. You are 115 m from an intersection when the traffic light turns red. Assume that your reaction time is 0.50 s and that your car brakes with constant acceleration.
Use first equation of motion
V = U - at
Since the car is going to rest, V = 0 and a = negative
0 = 14 - a × 0.5
0.5a = 14
a = 14 /0.5
a = 28 m/s^2
Let us use second equation of motion
S = Ut - 1/2at^2
S = 14 × 0.5 - 0.5 × 28 × 0.5^2
S = 7 - 3.5
S = 3.5 m
115 - 3.5 = 111.5
Therefore, you are 111.5 metres from the intersection (in m) when you begin to apply the brakes.
Answer:
The correct option is D
Explanation:
This question can be better understood when discussed using the Newton's first law of motion which states that an object would continue to move with a uniform speed (in a straight line) unless acted upon by an external force. What happens here (in the question) is that the bike rider would have continued moving at a constant speed (to the right) if not for the opposing force of the wind that acted against her (to the left). <u>This wind/force would cause her speed to reduce or slow down (as posited by the law)</u>.
25,000 Feet = 7620m
PE = mgh where m is mass, g is gravity accel: 9.8 n h is height
= 90 x 9.8 x 7620
= 6720840J
= 6.72MJ
F = ma where m is mass, a is accel = gravity = 9.8
= 90 x 9.8
= 882N
Accel = gravity = 9.8m/s^2
KE = 1/2mv^2 where m is mass n v is vel
if no wind resistance, PE leaving airplane = KE at net
6720840 = 1/2 x 90 x v^2
v^2 = 149352
v = 386.5m/s
