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natta225 [31]
3 years ago
5

Suppose you were bungee jumping from a bridge while blowing a hand-held air horn. How would someone remaining on the bridge hear

the pitch of the air horn as time increased?
Physics
2 answers:
castortr0y [4]3 years ago
7 0

Answer:

Pitch would decrease

Explanation:

According to Doppler's effect, the apparent frequency (pitch) of a sound changes if there is relative motion between the source and the listener.

As the distance increases between the source and the listener, the apparent frequency heard by the listener would be lower than the source frequency.

So, as the bungee jumper would go up in the air, the listener standing on the bridge would hear decreasing pitch.

Genrish500 [490]3 years ago
4 0

Answer:

The pitch will progressively lower

Explanation:

If i were bungee jumping from  a bridge while blowing a hand-held air horn and someone who remains on the bridge will hear a decreased pitch or frequency as the source is moving away from the stationary listener as per the Dooplers effect. Hence, the pitch will progressively lower as the source is moving away from the observer.

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A paintball’s mass is 0.0032kg. A typical paintball strikes a target moving at 85.3 m/s.
vekshin1

Answer:

A)  If the paintball stops completely the magnitude of the change in the paintball’s momentum is  p=0.273kg*m/s

B) If the paintball bounces off its target and afterward moves in the opposite direction with the same speed, the change in the paintball’s momentum is  p=0.546kg*m/s

C) A paintball bouncing off your skin in the opposite direction with the same speed hurts more than a paintball exploding upon your skin because of the strength exerted is twice than if it explodes.

Explanation:

Hi

A) We use the formula of momentum p=mv, so we have p=0.0032kg*85.3m/s=0.273kg*m/s

B) We use the same formula above, then due we have a change of direction at the same speed, therefore the change in the momentum is the double so

p=2*0.0032kg*85.3m/s=0.546kg*m/s.

C) The average strength of the force an object exerts during impact is determined by the amount the object’s momentum changes. therefore

F=\frac{\Delta p}{\Delta t}, as we don't have any data about the impact time but we know momentum is twice, time does no matter and strength is twice too.

4 0
4 years ago
During World War II, the United States government forced thousands of _____ to be relocated to internment camps.
iren2701 [21]

Answer:

Japanese Americans

Explanation:

prevented them from buying land and sent them back to japan after the war

hope this helps :)

8 0
2 years ago
Read 2 more answers
a 250.0 g snowball of radius 4.00 cm starts from rest at the top of the peak of a roof and rolls down a section angled at 30.0 d
g100num [7]

Answer:

The response to this question is as follows:

Explanation:

The whole question and answer can be identified in the file attached, please find it.

3 0
3 years ago
Which would be a common-sense practice in a lab environment?
algol13
Using safe research practices would be a very good common-sense practice in a lab environment.
6 0
3 years ago
Assume that a clay model of a lion has a mass of 0.225 kg and travels on the ice at a speed of 0.85 m/s. It hits another clay mo
Charra [1.4K]

Answer:

Final velocity will be equal to 0.321 m/sec

Explanation:

We have given mass of clay model of lion m_1=0.225kg

Its speed is 0.85 m/sec, so v_1=0.85m/sec

Mass of another clay model m_2=0.37kg

It is given that second clay is motionless

So its velocity v_2=0m/sec

Now according to conservation of momentum

Momentum before collision will be equal to momentum after collision

So m_1v_!+m_2v_2=(m_1+m_2)v, here v is velocity after collision

So 0.225\times 0.85+0.37\times 0+(0.225+0.37)v

0.595v=0.191

v = 0.321 m/sec

So final velocity will be equal to 0.321 m/sec  

5 0
3 years ago
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