Answer:
a,b) #_ {electron} = 1.64 10¹⁹ electrons, c) R = 19.54 Ω, d) V = 10.3 V
Explanation:
a and b) The current is defined as the number of electrons that pass per unit of time
let's look for the load
Q = I t
Q = 0.526 5
Q = 2.63 C
Let's use a direct rule of three proportions. If an electron has a charge of 1.6 10⁻¹⁹ C, how many electrons does 2.63 C have?
#_ {electron} = 2.63 C (1 electron / 1.6 10⁻¹⁹)
#_ {electron} = 1.64 10¹⁹ electrons
c) the resistance of a wire is given by
R = ρ l / A
where the resistivity of tungsten is 5.6 10⁻⁸ Ω
the area of the wire is
A = π r2 = π d²/4
we substitute
R = 
let's calculate
R = 5.6 10⁻⁸ 0.580 
R = 19.54 Ω
d) let's use ohm's law
V = i R
V = 0.526 19.54
V = 10.3 V
Answer:
I'll write it below
Explanation:
1) understand the parts.
2)read the scales
3)check the scale of your smallest divisions
4)clean the object you are measuring
5)If you have, unlock the screw
6)close the jaws
I hope this satisfies you sir.
If you have any questions related to this please feel free to ask me. I hope u will follow me and make this the brainliest answer.
Answer:
F = 2389.603 N
Explanation:
Given:
Mass m = 1,369.4 kg
Initial velocity u = 28.9 m/s
Final velocity v = 20 m/s
Time t = 5.1 s
Find:
Net force
Computation:
a = (v - u)/t
a = (20 - 28.9)/5.1
a = -1.745 m/s²
F = ma
F = (1369.4)(1.745)
F = 2389.603 N
Answer:
625000 N/ m
Explanation:
m= 20 kg
v= 30 m/s
x= 12 cm
k = ?
Here when the mass when hits at spring its speed is
Vi= 30 m/s
Finally it comes to rest after compressing for 12 cm
i-e Vf = 0 m/s
Distance= S= 12 cm = 0.12 m
using
2aS= Vf2 - Vi2
==> 2a ×0.12 = o- 30 × 30
==> a = 900 ÷ 0.24 = 3750 m/sec2
Now we know;
F = ma
F= -Kx
==> ma= -kx
==> 20 × 3750 = -K × 0.12
==> k = 625000 N/ m
I believe the best example of Newton's First Law of motion would be the example or illustration with the basketball player. An object will move in a straight line or a given direction at a constant speed unless or until another force acts upon the object, causing a change in speed and or direction.
