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Kipish [7]
2 years ago
14

What is the difference between work done by fuel and work done by moving object??​

Physics
2 answers:
Alex777 [14]2 years ago
4 0

Answer:

work done by fuel is chemical energy and work done by moving objects is kinetic energy

Explanation:

when work is done by object that object gains energy . when the work is done by an object that object loses energy because it is transferring it to something else .

Arturiano [62]2 years ago
3 0

Answer:

work done by fuel is conversion of chemical energy into mechanical whereas work done by moving object is due to its displacement by the application of force. actually, both of them give same meaning

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What cloud makes hail
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Answer:

Cumulonimbus

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3 years ago
Electrostatics is described as the study of electric charges that can be collected and held in place. Is this true or false?
Rasek [7]

Electrostatics is described as the study of electric charges that can be collected and held in place.

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7 0
1 year ago
Two 2 kg masses is placed at either end of a rod that has a mass of .5 kg and a length of 3 m. What is the moment of inertia if
sergij07 [2.7K]

Explanation:

a) I=\displaystyle \sum_{i}m_ir_i^2

where r_i is the distance of the mass m_i from the axis of rotation. When the axis of rotation is placed at the end of the rod, the moment of inertia is due only to one mass. Therefore,

I= mr^2 = (2\:kg)(3\:m)^2 = 18\:kg-m^2

b) When the axis of rotation is placed on the center of the rod, the moment is due to both masses and the radius r is 1.5 m. Therefore,

\displaystyle I= \sum_{i}m_ir_i^2 = 2(2\:kg)(1.5\:m)^2 = 9\:kg-m^2

7 0
3 years ago
PLEASE HELP A student climbs to the top of a press box where the cameras are. He wonders how many meters he is off of the ground
Feliz [49]

The height of the rail on top of the press box where the ball was dropped from is 11.025 m.

The given parameters:

  • Time of motion of the ball, t = 1.5 s
  • Let the height of the rail = h

<h3>Maximum height of fall;</h3>
  • The maximum height through which the ball was dropped from is calculated by applying second equation of motion;

h = v_0_y t + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\h = \frac{1}{2} gt^2\\\\h = \frac{1}{2} (9.8) (1.5)^2\\\\h = 11.025 \ m

Thus, the height of the rail on top of the press box where the ball was dropped from is 11.025 m.

Learn more about height of projectiles here: brainly.com/question/10008919

3 0
2 years ago
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