Answer:
a. 150 N
Explanation:
Gravitational Force: This is the force that act on a body under gravity.
The gravitational force always attract every object on or near the earth's surface. The earth therefore, exerts an attractive force on every object on or near it.
The S.I unit of gravitational force is Newton(N).
Mathematically, gravitational force of attraction is expressed as
(i) F = GmM/r² ........................ Equation 1 ( when it involves two object of different masses on the earth)
(ii) F = mg ............................... Equation 2 ( when it involves one mass and the gravitational field).
Given: m = 17 kg, g = 8.8 m/s²
Substituting into equation 2,
F = 17(8.8)
F = 149.6 N
F ≈ 150 N.
Thus the gravitational force = 150 N
The correct option is a. 150 N
Answer:
t = 2s
Explanation:
When you're looking for instantaneous portions of a graph, of any sort really, it means you're observing a rate at a single point in time [or possibly some other variable]. It's sorta like a snapshot of a rate as opposed to an average rate over an interval. After choosing this rate we'll typically draw a straight, tangent line through it to indicate it's slope. (Tangent lines are just lines that only touch a single point on a graph or shape.)
Another thing to take note of are the values of the graph's major axes. The "y-axis" corresponds to velocity in meters per second, while the "x-axis" corresponds to time in seconds. Normally when relating the two we put "y" over the "x" and say that at any point there are "y[units]" per "x[units]". Though with instantaneous rates, we say the value of "x" is "1"; for reasons I can try to further explain later if you'd like.
With the above information in mind we can turn our attention to your graph. You're told to find the point on this graph where the instantaneous rate of acceleration is -2 m/s². The only place where the graph reflects an instantaneous rate of -2m/s² is at t = 2s. At t = 2, the rate comes out to (2[m/s]/1s), which simplifies to 2m/s². If you then draw the tangent line through the point, you'll find that the line is decreasing (going down from left to right) which means that the instantaneous rate is negative.
So at t = 2s, we have an instantaneous acceleration of -2m/s².
Assuming a perpetual inventory system and using the weighted average method, the weighted average unit is determined as $11.44 after the October 22 purchase.
<h3>What is Weighted Average Cost (WAC)?</h3>
The Weighted Average Cost (WAC) method of inventory valuation in accounting uses a weighted average to establish the COGS and inventory levels.
The price of the products up for grabs is divided by the quantity of them in the weighted average cost technique.
The WAC technique is appropriate under both GAAP and IFRS accounting. Weighted Average Cost (WAC) Method Formula
<h3>Weighted Average Cost</h3>
Weighted Average Unit Costs = [360 units×$12 + (320-180) ×$10] / [360+(320-180)]units}
Weighted Average Unit Costs = $5720 / 500 units
Weighted Average Unit Costs = $11.44
Costs of goods that are offered for sale are calculated using beginning inventory value plus acquisitions.
Units available for sale are the number of units that can be sold by a company or the total number of units that are in its inventory.
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A wave transfers energy from the source outward in the
direction of wave motion.
To add, <span>in physics, a </span>wave<span> is an oscillation accompanied by a transfer of
energy that travels through a medium (space or mass). Frequency refers
to the addition of time.</span>