Power can be defined as the distance over which work was done. how much work can be done in a given time. all the work in a give
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The representation of this problem is shown in Figure 1. So our goal is to find the vector 
. From the figure we know that:
From geometry, we know that:
Then using vector decomposition into components:
Therefore:
So if you want to find out <span>how far are you from your starting point you need to know the magnitude of the vector, that is:
</span>
Finally, let's find the <span>compass direction of a line connecting your starting point to your final position. What we are looking for here is an angle that is shown in Figure 2 which is an angle defined with respect to the positive x-axis. Therefore:
</span>
From geometry, we know that:
Then using vector decomposition into components:
Therefore:
So if you want to find out <span>how far are you from your starting point you need to know the magnitude of the vector
</span>
Finally, let's find the <span>compass direction of a line connecting your starting point to your final position. What we are looking for here is an angle that is shown in Figure 2 which is an angle defined with respect to the positive x-axis. Therefore:
</span>
In this problem we have the electric field intensity E:
E = 6.5 × newtons/coulomb
We have the magnitude of the load:
q = 6.4 × coulombs
We also have the distance d that the load moved in a direction parallel to the field 1.2 × meters.
We know that the electric potential energy (PE) is:
PE = qEd
So:
PE = (6.4 × )(6.5 ×
)(1.2 ×
)
PE = 5.0 x joules
None of the options shown is correct.