Answer:
The average emf induced in the coil is 175 mV
Explanation:
Given;
number of turns of the coil, N = 1060 turns
diameter of the coil, d = 20.0 cm = 0.2 m
magnitude of the magnetic field, B = 5.25 x 10⁻⁵ T
duration of change in field, t = 10 ms = 10 x 10⁻³ s
The average emf induced in the coil is given by;
where;
A is the area of the coil
A = πr²
r is the radius of the coil = 0.2 /2 = 0.1 m
A = π(0.1)² = 0.03142 m²
Therefore, the average emf induced in the coil is 175 mV
Answer:
the maximum deformation undergone by the spring = 47.46 cm
Explanation:
Using conservation of momentum:
where:
Then;
v = 19.375 m/s
However ; using conservation of energy to determine the maximum deformation undergone by the spring ; we have:
x = 0.4746 m
x = 47.46 cm
Thus, the maximum deformation undergone by the spring = 47.46 cm
Answer:
The electric potential (voltage) produced by a point charge
, at any point in space, is given by the following equation:
Where:
is the Coulomb's constant
is the distance
The result is a scalar quantity, is defined as the electric potential energy per unit of charge and determines the electric influence exerted by the charge on that point of space.