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pav-90 [236]
2 years ago
13

A housefly walking across a clean surface can accumulate a significant positive or negative charge. In one experiment, the large

st positive charge observed was +70 pC. A typical housefly has a mass of 12mg. A.) Explain how the housefly could accumulate an electric charge by walking across a surface? B.) What magnitude and direction electric field would be necessary to levitate a housefly with a maximum charge? Could such a field exist in air?
Physics
1 answer:
nalin [4]2 years ago
5 0

Answer:

1681714.28571 N/C

Yes it could exist

Explanation:

m = Mass of housefly = 12 m

q = Charge = 70 pC

g = Acceleration due to gravity = 9.81 m/s²

E = Electric field

When an object accumulates charge it means that it is gaining electrons making it negatively charged. This is the concept of static electricity.

Here, the electric force and the graviational force will balance each other

F_e=W\\\Rightarrow qE=mg\\\Rightarrow E=\frac{mg}{q}\\\Rightarrow E=\frac{12\times 10^{-6}\times 9.81}{70\times 10^{-12}}\\\Rightarrow E=1681714.28571\ N/C

1681714.28571 N/C of electric field would be required to levitate

The direction of the electric field would be upwards vertically.

In air the critical value of electric field is 3\times 10^6\ N/C which is more than the critical value of electric field in air. So, the electric field can exist.

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Answer:

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Explanation:

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2 years ago
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Answer:

Q_T=63313.5\ J

Explanation:

Given:

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<em>Assuming that no heat is lost in the surrounding.</em>

<u>We know:</u>

Q=m.c.\Delta T

<u>Now the total heat given by the steam to form water at the given conditions:</u>

Q_T=Q_{Lv}+Q_w ..............................(1)

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Q_{Lv}= latent heat given out by vapour to form water of 100°C

Q_w= heat given by water of 100°C to come at 34°C.

putting respective values in eq. (1)

Q_T=m(L+c.\Delta T)

Q_T=25(2256+4.19\times 66)

Q_T=63313.5\ J

is the heat transferred to the skin.

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