Answer:
Explanation:
Let fuel is released at the rate of dm / dt where m is mass of the fuel
thrust created on rocket
= d ( mv ) / dt
= v dm / dt
this is equal to force created on the rocket
= 220 dv / dt
so applying newton's law
v dm / dt = 220 dv / dt
v dm = 220 dv
dv / v = dm / 220
integrating on both sides
∫ dv / v = ∫ dm / 220
lnv = ( m₂ - m₁ ) / 220
ln4000 - ln 2500 = ( m₂ - m₁ ) / 220
( m₂ - m₁ ) = 220 x ( ln4000 - ln 2500 )
( m₂ - m₁ ) = 220 x ( 8.29 - 7.82 )
= 103.4 kg .
Answer:
Explanation:

Subtract both sides by
:

Divide both sides by -2*a:

Add both sides by
:

Subtract both sides by
:

Answer:2m/s²
Explanation: Well F=MA so sice F=4N and M=2kg let's plug in the values
4N=2KG*A
A=4N/2KG
A=2m/s²
For electrical devices . . .
Power dissipated = (voltage) x (current) =
(12 V) x (3.0 A) = 36 watts .
1 watt means 1 joule per second
(36 joule/sec) x (60 sec/min) x (10 min) = 21,600 joules
Answer:
57 N
Explanation:
Were are told that the force
of gravity on Tomas is 57 N.
And it acts at an inclined angle of 65°
Thus;
The vertical component of the velocity is; F_y = 57 sin 65
While the horizontal component is;
F_x = 57 cos 65
Thus;
F_y = 51.66 N
F_x = 24.09 N
The net force will be;
F_net = √((F_y)² + (F_x)²)
F_net = √(51.66² + 24.09²)
F_net = √3249.0837
F_net = 57 N