Answer:
A.)
H0: μ ≤ 31
H1: μ > 31
B.)
H0: μ ≥ 16
H1: μ < 16
C.)
Right tailed test
D.)
If Pvalue is less than or equal to α ; we reject the Null
Step-by-step explanation:
The significance level , α = 0.01
The Pvalue = 0.0264
The decision region :
Reject the null if :
Pvalue < α
0.0264 > 0.01
Since Pvalue is greater than α ; then, we fail to reject the Null ;
Then there is no significant evidence that the mean graduate age is more Than 31.
B.)
H0: μ ≥ 16
H1: μ < 16
Null Fluid contains 16
Alternative hypothesis, fluid contains less than 16
One sample t - test
C.)
Null hypothesis :
H0 : μ ≤ 12
. The direction of the sign in the alternative hypothesis signifies the type of test or tht opposite direction of the sign in the null hypothesis.
Hence, this is a right tailed test ; Alternative hypothesis, H1 : μ > 12
d.)
If Pvalue is less than or equal to α ; we reject the Null.
Im late do you still need the answer aa it wont send aaa
Answer:
D
Step-by-step explanation:
If it was 6 degrees cooler on Monday than it was on Sunday, but also having Tuesday be 4 degrees warmer than Monday, Wednesday would have to be 2 degrees cooler than Tuesday because it is a number that would comply with the limits
1. Know what you're looking for:
The range is the difference between the lowest and highest values.
Your weight is 145.2 and can vary from the actual weight by maximum 0.3 lbs less or maximum 0.3 lbs more.
2. Calculate your lowest and highest values :
Lowest : 145.2 - 0.3 = 144.9 lbs
Highest : 145.2 + 0.3 = 145.5 lbs
3. Calculate the range of actual weights of the object :
145.5 - 144.9 = 0.6 lbs
--> The answer is: <u>The range of actual weights of the object is 0.6 lbs.</u>
There you go! I really hope this helped, if there's anything just let me know! :)
Answer:
30
Step-by-step explanation:
Because of the following statement is not true no.of atoms
