First, you have to understand that when you see a 'complex fraction' like this, the top number is a numerator, and the two bottom numbers are both denominators.

Way-1:

Take the top fraction . . . 2/2 . That's equal to 1 . So the whole thing is <em>1/3</em>.

Way-2:

Multiply the bottom two denominators. Then the whole thing is 2/(2·3) . That's the same thing as 2/6 . Simplify that, and you have <em>1/3</em> .

7 0

3 years ago

!!Plz urgent help!!

Firdavs [7]

Answer:

890 beads can be fitted in the triangular prism.

Step-by-step explanation:

If we can fill the spherical beads completely in the triangular prism,

Volume of the triangular prism = Volume of the spherical beads

Volume of triangular prism = Area of the triangular base × Height

From the picture attached,

Area of the triangular base = $\frac{1}{2}(\text{Base})(\text{Height})$

= $\frac{1}{2}(AB)(BC)$

By applying Pythagoras theorem in the given triangle,

AC² = AB² + BC²

(13)² = 5² + BC²

169 = 25 + BC²

BC² = 144

BC = 12

Area of the triangular base = $\frac{1}{2}(5)(12)$

= 30 cm²

Height of the triangular prism = 18 cm

Volume of the triangular prism = 30 × 18

= 540 cm³

Volume of one spherical bead = $\frac{4}{3}\pi r^{3}$

= $\frac{4}{3}\pi (0.525)^{3}$

= 0.606 cm³

Let there are 'n' beads in the triangular prism,

Volume of 'n' beads = Volume of the prism

540 = 0.606n

n = 890.90

n ≈ 890

Therefore, 890 beads can be fitted in the triangular prism.

3 0

2 years ago