Use the properties of exponents to rewrite y=e^-0.75t in the form of a(1-r)^t

Mathematics

1 answer:

Ivahew [28]2 years ago

5 0

Answer: y = (1 - 0.527)^t

Step-by-step explanation:

y=e^(-0.75t)

y=(e^-0.75)^t

y= 0.47236655^t

1 - 0.47236655 = 0.52763345

y = (1 - 0.527)^t

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<h3>What is logarithm and some of its useful properties?</h3>

When you raise a number with an exponent, there comes a result.

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Then, you can write 'b' in terms of 'a' and 'c' using logarithm as follows

Some properties of logarithm are:

$log_a(b) = log_a(c) \implies b = c\\\\\log_a(b) + log_a(c) = log_a(b \times c)\\\\log_a(b) - log_a(c) = log_a(\frac{b}{c})\\\\log_a(b^c) = c \times log_a(b)\\\\log_b(b) = 1\\\\ log_a(b) + log_b(c) = log_a(c)$

Log with base e = 2.71828... is written as $\ln(x)$ simply.

Log with base 10 is written as $\log(x)$ simply.

The given equation is:

$\log_4(x+3) = \log_2(2 +x)$

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