The twin primes between 1 and 100 are; (3, 5), (5, 7), (11, 13), (17, 19), (29, 31), (41, 43), (59, 61), (71, 73). Hope this helped<3
Answer:
2.75 mol
Explanation:
Given data:
Mass of Nitrogen = 38.5 g
Moles of ammonia produced = ?
Solution:
Chemical equation:
N₂ + 3H₂ → 2NH₃
Number of moles of nitrogen:
Number of moles = mass/ molar mass
Number of moles = 38.5 g/ 28 g/mol
Number of moles = 1.375 mol
Now we will compare the moles of ammonia and nitrogen from balance chemical equation.
N₂ : NH₃
1 : 2
1.375 : 2×1.375 = 2.75 mol
Thus 2.75 moles of ammonia are produced from 38.5 g of nitrogen.
The latent heat of vaporization 5gram of steam converted to liquid at 100°C is 11.3 KJ.
The latent heat of vaporization for a given substance tells you how much energy is required for one mole of that substance to undergo a phase transition or go from a liquid to a gas, at its boiling point.
Joules per gram, an alternative to the more popular kilojoules per mole, are used to express the latent heat of vaporization for water.
Therefore, we must determine how many kilojoules per gram are needed for a certain sample of water to transition from a liquid to a vapor at its boiling point.
As you know, the conversion factor that exists between Joules and kilojoules is 1 kJ = 10³ J
2260 J/g will be equivalent to
As we know,
2260 = 2.26 . 10³
which means that 2.26 .10³ = 2260J
This is the latent heat of vaporization 5gram of water= 2260J/g × 5g
= 11,300J
= 11.3 KJ
Therefore, the latent heat of vaporization 5gram of steam converted to liquid at 100°C is 11.3 KJ.
Learn more about latent heat here:
brainly.com/question/12775811
#SPJ4
Answer:
Smithers thinks that a special juice will increase the productivity of workers. He creates two groups of 50 workers each and assigns each group the same task (in this case, they're ... Group A is given the special juice to drink while they work. Group ... 1. Control Group. Group B. 2. Independent Variable. volume of special juice.
Explanation: