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BlackZzzverrR [31]
3 years ago
15

What part of the atom determines if it will combine or break apart from other substances

Chemistry
1 answer:
enyata [817]3 years ago
7 0

The combination of an atom with other atom is bonding. Or break apart from other substance is breaking of interaction.

The bonding or interaction (inter-atomic) are due orbitals and electrons present in these orbitals

The atom consists of

a) a central nucleus which has proton and neutrons: they do not take part in chemical reactions

b) the part other than nucleus which has shells, sub shells and orbitals

These orbitals have electrons.

So the outer part of nucleus takes part in any combination with other substance

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7 0
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The heat of reaction for the combustion of propane is –2,045 kJ. This reaction is: C3H8(g) +502 (g) 3CO2 (g) + 4H2O (g). Determi
Ede4ka [16]

Answer:

\Delta _fH_{C_3H_8}=-102.7kJ/mol

Explanation:

Hello,

In this case, we can consider that the given heat of combustion is indeed the heat of reaction since it corresponds to the combustion of propane, which is computed by using the heat formation of all the involved species as shown below:

\Delta _cH=3*\Delta _fH_{CO_2}+4*\Delta _fH_{H_2O}-\Delta _fH_{C_3H_8}-5*\Delta _fH_{O_2}

Thus, since the heat of formation of gaseous carbon dioxide is -393.5 kJ/mol, water -241.8 kJ/mol and oxygen 0 kJ/mol, the heat of formation of propane is:

\Delta _fH_{C_3H_8}=3*\Delta _fH_{CO_2}+4*\Delta _fH_{H_2O}-5*\Delta _fH_{O_2}-\Delta _cH\\\\\Delta _fH_{C_3H_8}=3*(-393.5)+4*(-241.8)-5*0-(-2045)\\\\\Delta _fH_{C_3H_8}=-102.7kJ/mol

Best regards.

8 0
3 years ago
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