<u> </u>Dilution consists of lowering the amount of solute per unit volume of solution. It is achieved by adding more diluent to the same amount of solute.

This is deduced when thinking that both the dissolution at the beginning and at the end will have the same amount of moles.

M1 = 6.01 M stock solution concentration

M2 = 0.3624 M diluted solution concentration

V2 =100 mL diluted solution volume

V1 = ? stock solution volume

M1 * V1 = M2 * V2

$V1=\frac{M2*V2}{M1} =\frac{0.3624M*100mL}{6.01M} =6.0299 mL$

4 0

3 years ago

A group 2 metal carbonate has a mass of 84 g/mol. Identify the group 2 metal X using its chemical formula.

zepelin [54]

Answer:

Magnesium

0.003mole

Explanation:

The problem here entails we find the metal in the carbonate.

For group 2 member, let the metal = X;

The carbonate is XCO₃;

If we sum the atomic mass of the elements in the metal carbonate, we should arrive at 84g/mol

Atomic mass of C = 12g/mol

O = 16g/mol

Atomic mass of X + 12 + 3(16) = 84

Atomic mass of X = 84 - 60 = 24g/mol

The element with atomic mass of 24g is Magnesium

Number of moles in 0.3g of CaCO₃:

Molar mass of CaCO₃ = 40 + 12 + 3(16) = 100g/mol

Number of moles = $\frac{mass}{molar mass}$

Number of moles = $\frac{0.3}{100}$ = 0.003mole

7 0

3 years ago