Question

The electric force between two charged objects is 0.24 newtons. If the distance between them is increased by a factor of 4, what will be the new force?
A.
0.015 newtons
B.
0.03 newtons
C.
0.06 newtons
D.
0.12 newtons
E.
0.36 newtons

Answer 1

Answer:

A. 0.015 newtons

Explanation:

The electric force of two charged objects will be directly proportional to the charge of both objects. The force also inversely proportional to the square of the distance. The distance of the object is changed 4 times longer than before. In short, the force will be 4^2= 16 times lower than before.

The calculation will be:

F= $\frac{kQ1Q2}{r^{2} }$

F1/F2= $\frac{kQ1Q2}{r^{2} }$/ $\frac{kQ1Q2}{4r^{2} }$

0.24N/F2= $\frac{16r^{2} }{r^{2} }$

0.24N= 16F2

F2= 0.24N/ 16= 0.015N