Answer:
6.30 M⁻¹s⁻¹.
Explanation:
As the reaction is first order with respect to a and b.
<em>The rate of the reaction = k [a][b],</em>
where, k is the rate constant of the reaction.
The rate of the reaction = 2.65 × 10⁻⁴ M/s,
[a] = 1.60 × 10⁻² M,
[b] = 2.67 × 10⁻³ M.
∴ k = (the rate of the reaction / [a][b]) = (2.65 × 10⁻⁴ M/s) / (1.60 × 10⁻² M)( 2.67 × 10⁻³ M) = 6.30 M⁻¹s⁻¹.
Answer:
<u><em>(A.) three dimensional folded structure of the protein</em></u>
Explanation:
The secondary structure of a protein is a regular structure built from interactions between neighboring amino acids as the polypeptide starts to fold or coil into its functional three-dimensional shape.
The two kinds of secondary structures arising from this polypeptide 'flexing' are either the α-helix and β-pleated structures, all of which are vital to globular and fibrous proteins.
Answer:
A. 0.064mol
B. 0.85mol
C. 1500mL
Explanation:
A. Molarity = 0.33M
Volume = 195mL = 195/1000 = 0.195L
Mole =?
Molarity = mole /Volume
Mole = Molarity x Volume
Mole = 0.33 x 0.195
Mole = 0.064mol
B. Molarity = 1.7M
Volume = 500mL = 500/1000 = 0.5L
Mole =?
Molarity = mole /Volume
Mole = Molarity x Volume
Mole = 1.7 x 0.5
Mole = 0.85mol
C. C1 = 12M
V1 = 50mL
C2 = 0.4M
V2 =?
Using the dilution formula C1V1 = C2V2, we find the volume of the diluted solution as follows:
C1V1 = C2V2
12 x 50 = 0.4 x V2
Divide both side by 0.4
V2 = (12 x 50) /0.4
V2 = 1500mL
Answer: 177g
Explanation:
Aw 12 = 6.02214076*10^23 atoms
mass = 12*88.70^23/6.022*10^23
Answer:
For NADH; P:O = 2.5
For FADH
₂; P : O = 1.5
Explanation:
The P:O (phosphate:oxygen) ratio represents the amount of inorganic phosphate, Pi used per atom of oxygen consume to synthesize ATP.
The Chemiosmotic theory predicts H⁺:O and H⁺:ATP ratios. Experimentally these appear to be 10 and 4 respectively when NADH is the substrate, equivalent to a P:O ratio of 2.5, and 6 and 4 respectively for FAD-linked substrates (e.g. succinate), equivalent to a P:O ratio of 1.5.
1. Electron flow from NADH to O₂ pumps protons at three sites to yield 3 ATP (P:O = 2.5)
For NADH: 10 H
⁺ translocated/O (2e
-)
ATP/2e
- = (10 H⁺/ 4 H
+) = 2.5
2. Succinate (via FADH2) bypasses site 1 giving 2 ATP (P : O = 1.5)
For FADH
₂= 6 H
⁺/O(2e
-
)
ATP/2e
- = (6 H
+/ 4 H
+) = 1.5
