Answer:
The atoms of noble gases already have complete outer shells, so they have no tendency to lose, gain, or share electrons. This is why the noble gases are inert and do not take part in chemical reactions. The table summarises the electronic configurations of elements in groups 1, 7 and 0.
Explanation:
The atoms of noble gases already have complete outer shells, so they have no tendency to lose, gain, or share electrons. This is why the noble gases are inert and do not take part in chemical reactions. The table summarises the electronic configurations of elements in groups 1, 7 and 0.
The actual size of something times the magnification is equal to the size of the appearance of the object in the image. Therefore, to find the magnification, divide the size of the image by the actual size of the object.
Answer:
Compound A: 1-bromo-1-methylcyclohexane
Compound B: 1-methylcyclohex-1-ene
Explanation:
In this question, we can start with the <u>I.D.H</u> (<em>hydrogen deficiency index</em>):
In the formula we have 7 carbons, 13 hydrogens, and 1 Br, so:
We have an <u>I.D.H value of one</u>. This indicates that we can have a <u>cyclic structure or a double bond</u>.
We have to keep in mind that the Br atom must be bonded to a t<u>ertiary carbon</u>. <u>We can not have a double bond</u> because in the ozonolysis reaction we have only <u>1 product</u>, therefore, we can not have a double bond in the initial molecule (if we have a double bond in the initial molecule we will have more than 1 product in the ozonolysis reaction).
With this in mind, we will have a <u>cyclic structure</u>. If we have 7 carbons and we need a tertiary alkyl halide. We can have a cyclic structure of 6 members and a methyl group bonded to a carbon that also is bonded to a Br atom <u>(1-bromo-1-methylcyclohexane).</u>
In the reaction with 
we will have an <u>elimination reaction</u>. In other words, we have the production of a double bond inside of the cyclic structure <u>(1-methylcyclohex-1-ene)</u>.
See figure 1 for further explanations.
I hope it helps!
Answer:
Explanation:
Number of moles of CuCl2 initially present = volume * molar concentration
= 0.134 * 8
= 1.072 mol.
Molar mass of CuCl2 = 63.5 + (2*35.5)
= 134.5 g/mol
Mass of CuCl2 = molar mass * number of moles
= 134.5 * 1.072
= 144.184 g
Mass of CuCl2 in 48 ml = 5.89 g in 48 ml
Volume = 5.89 * (48/144.184)
= 1.96 ml.
Answer is: Te (tellurium).
During electron capture, iodine-123 f<span>orm the nearly-stable nuclide tellurium-123.
</span>In beta
plus decay (atomic number Z is decreased by one), a proton is converted to a neutron
and positron and an electron neutrino, so mass <span>number does not
change.
</span>Iodine-123 is a radioactive isotope of iodine used in nuclear medicine imaging.<span>
</span>
