<em>Answer:</em>
- Organic compounds are those which are derivatives of hydrocarbons. They are classified into following functional groups.
<em>Alkane: </em>
- Alkane are simplest hydrocarbons.
- They have general formula CnH2n+2. These hydrocarbons contain single bond.
- For example ethane , H3C----CH3.
<em>Alkene:</em>
- Alkene are most reactive.
- They have general formula CnH2n.
- These contain double bond in their structure.
- For example , ethene, H2C=CH2
<em>Alkyne:</em>
- These are less less reactive as compare to alkenes.
- They have general formula CnH2n-2.
- They contain triple bonds in their structure.
- For example Acetylene HC≡CH
<em>Alcohol:</em>
Alcohol have functional group OH. They have general formual R---OH, R may be alkyl group.For example Ethanol H3CH2C---OH
<em>Amine:</em>
- Amine contain NH2 F.G.
- They have general formula R---NH2.
- There are three types of amine like primary, secondary and tertiary amine.
- For example H3CH2C---NH2
<em>Aldehyde:</em>
- Aldehydes have CHO F.G .
- They have general formula R--CHO.
- For example H3CH2C---CHO
<em>Ketone:</em>
- Ketones have R--CO--R functional group.
- For example acetone H3C---CO---CH3
<em>Carboxylic acid:</em>
- They functional group COOH.
- Their general formula is R---COOH.
- For example Acetic acid H3C---COOH
Answer:
1.0 x 10⁻⁸ M.
Explanation:
<em>∵ [H⁺][OH⁻] = 10⁻¹⁴.
</em>
∵ [H⁺] = 100 [OH⁻].
∴ 100 [OH⁻][OH⁻] = 10⁻¹⁴.
∴ 100 [OH⁻]² = 10⁻¹⁴.
[OH⁻]² = 10⁻¹⁴/ 100 = 1.0 x 10⁻¹⁶.
<em>∴ [OH⁻] = √(1.0 x 10⁻¹⁶) = 1.0 x 10⁻⁸ M.
</em>
<h2>
Answer:</h2>
<em>Hello, </em>
<h3><u>QUESTION)</u></h3>
During telophase, the cell, each pole of which inherits the same number of single chromosomes, begins to divide into 2: this is cytodieresis.
Answer:
conc. fuming, 1 mol H2SO4
Dilute NaOH
Br2
Dilute H2SO4
Explanation:
The synthesis of ortho-bromophenol follows the reaction sequence shown in the image attached.
First of all, the phenol is sulphonated using concentrated sulphuric acid at 100°C. Carrying out the reaction at 100°C ensures that the para-isomer predominates. Lower temperatures favour the formation of the ortho isomer. Dilute sodium hydroxide is added before the addition of bromine.
Bromine molecule is then added. The incoming electrophile now attaches to the ortho position. Dilute acid is added at 100°C to remove the -SO3H thereby obtaining the Ortho-bromophenol
Answer:
Six atoms.
=)
Explanation:
The number outside the brackets (2), should be multiplied by the number of atoms inside the brackets. Thus, there will be 2 chlorine atoms and 6 oxygen atoms.
=)