Question

1) How many moles of gas occupy 58 L at a pressure of 2.2 atmospheres and a temperature

Answer 1

Here, we need to solve this problem using Ideal gas law ( PV=nRT).

Where –

• P = Pressure in atm
• V = Volume in L
• n = moles
• R = Ideal gas law constant
• T = Temperature in K

Now, according to the question –

• V = 58 L
• P = 2.2 atm
• T = 313 K
• R = 0.0821 atm L/ mol K

Calculation –

$\qquad$ $\pink{\twoheadrightarrow\bf PV = nRT}$

$\qquad$ $\twoheadrightarrow\sf n = \dfrac{PV}{RT}$

$\qquad$ $\twoheadrightarrow\sf n = \dfrac{ 2.2 \: \:\times 58 \: } {0.0821 \times 313}$

$\qquad$ $\twoheadrightarrow\sf n = \dfrac{ 2.2 \times 58}{0.0821 \times 313}$

$\qquad$ $\twoheadrightarrow\sf n =\dfrac{127.6}{25.7}$

$\qquad$ $\pink{\twoheadrightarrow\bf n = 4.9656 \: moles }$

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Answer 2

Given Information ,

• Volume ,V = 58 L
• Pressure ,P = 2.2 atm
• Temperature ,T = 313

We have to find the number of moles .

We use here " Ideal Gas Equation" which is

• PV = nRT

where

n is number of moles

R is universal gas Constant

T is temperature

P is pressure

V is volume

On substituting the value we get

➣ 2.2 × 58 = n × 0.0821 × 313

➣ 127.6 = n × 25.70

➣ 127.6/25.70 = n

➣ 4.96 = n

➣ 5 ≈ n

So, the number of moles are 5 .