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MArishka [77]
3 years ago
15

4. Which of these metals is a pure element? Brass Bronze Silver Steel 5. C is the correct chemical symbol for ....... Calcium Ca

rbon Chlorine Cobalt 6. Which of these substances is an element? Air Fire Oxygen Water
Chemistry
2 answers:
pickupchik [31]3 years ago
5 0

Answer:

4) Silver (Rest are alloys)

5) Carbon (It stands for C)

6) Oxygen (Rest of them are either compounds or mixtures)

Gala2k [10]3 years ago
3 0

Answer:

4) Silver

5) Carbon

6) Oxygen

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Plz help me with these three please please !!!!!
Novay_Z [31]

Explanation:

Cations are positively charged ions with fewer electrons than protons. To partake in reaction, metals lose electrons to achieve a stable octet configuration. It has lost valence electrons and wold have a positive charge associated with it.

Potassium is a group 1 element. A metal.

Potassium has 1 valence electron so it loses the valence electron to form a stable octet.

A potassium ion has a positive charge and therefore cannot be an anion but is a cation.

The group number pretty much denotes the number of valence electrons.

Group 1 = 1

Group 2 = 2

Group 17 = 7

Group 18 = 8

4 0
3 years ago
when you decrease the distance between two magnets that are repelling, you increase the magnetic force. True or false?
kupik [55]

Answer:

False that would be crazy but cool

3 0
3 years ago
Read 2 more answers
What are the physical properties of toothpaste
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The whitening toothpastes showed differences in their physical-chemical properties. All toothpastes promoted changes to the surface, probably by the use of a bleaching agent.
5 0
3 years ago
For the equilibrium
Mamont248 [21]

Answer:

Equilibrium concentrations of the gases are

H_2S=0.596M

H_2=0.004 M

S_2=0.002 M

Explanation:

We are given that  for the equilibrium

2H_2S\rightleftharpoons 2H_2(g)+S_2(g)

k_c=9.0\times 10^{-8}

Temperature, T=700^{\circ}C

Initial concentration of

H_2S=0.30M

H_2=0.30 M

S_2=0.150 M

We have to find the equilibrium concentration of gases.

After certain time

2x number of moles  of reactant reduced and form product

Concentration of

H_2S=0.30+2x

H_2=0.30-2x

S_2=0.150-x

At equilibrium

Equilibrium constant

K_c=\frac{product}{Reactant}=\frac{[H_2]^2[S_2]}{[H_2S]^2}

Substitute the values

9\times 10^{-8}=\frac{(0.30-2x)^2(0.150-x)}{(0.30+2x)^2}

9\times 10^{-8}=\frac{(0.30-2x)^2(0.150-x)}{(0.30+2x)^2}

9\times 10^{-8}=\frac{(0.30-2x)^2(0.150-x)}{(0.30+2x)^2}

By solving we get

x\approx 0.148

Now, equilibrium concentration  of gases

H_2S=0.30+2(0.148)=0.596M

H_2=0.30-2(0.148)=0.004 M

S_2=0.150-0.148=0.002 M

3 0
3 years ago
What part is the independent variable and what part is the dependent variable in the scenario: The blood pressure of a soldier i
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What part is the independent variable and what part is the dependent variable of the seminary the blood pressure of a soldier is measured while he’s resting soldiers and exposed to a stressful environment and his blood pressure is measured in
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