The distance between earth and sun is 15000000km. Light takes 499 seconds to reach earth from sun. Calculate the speed of light
2 answers:
To solve the problem we must know about the relationship between Speed, distance, and Time.
<h3>What is the relationship between Speed, distance, and Time?</h3>We know that sped, distance, and time all are in a relationship to each other. this relationship can be given as,
The speed of the light is 30,060.12 km/sec.
Given to us
- The distance between the earth and the sun is 15000000km
- Light takes 499 seconds to reach earth from the sun.
We know that speed can be described as,
Therefore,
<h3>What is the speed of the light?</h3>Substitute the value,
Hence, the speed of the light is 30,060.12 km/sec.
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Answer:
L = μ₀ n r / 2I
Explanation:
This exercise we must relate several equations, let's start writing the voltage in a coil
= - L dI / dt
Let's use Faraday's law
E = - d Ф_B / dt
in the case of the coil this voltage is the same, so we can equal the two relationships
- d Ф_B / dt = - L dI / dt
The magnetic flux is the sum of the flux in each turn, if there are n turns in the coil
n d Ф_B = L dI
we can remove the differentials
n Ф_B = L I
magnetic flux is defined by
Ф_B = B . A
in this case the direction of the magnetic field is along the coil and the normal direction to the area as well, therefore the scalar product is reduced to the algebraic product
n B A = L I
the loop area is
A = π R²
we substitute
n B π R² = L I (1)
To find the magnetic field in the coil let's use Ampere's law
∫ B. ds = μ₀ I
where B is the magnetic field and s is the current circulation, in the coil the current circulates along the length of the coil
s = 2π R
we solve
B 2ππ R = μ₀ I
B = μ₀ I / 2πR
we substitute in
n ( μ₀ I / 2πR) π R² = L I
n μ₀ R / 2 = L I
L = μ₀ n r / 2I
The Earth’s average orbital speed expressed in kilometers per hours is 107225.5 Km/hr and the mass of the sun is 2.58 x Kg
Linear speed is the product of angular speed and the maximum displacement of the particle. That is,
V = Wr
Where
- V = Linear speed
- W = Angular speed
- r = Radius
Given that the earth orbits the sun at an average circular radius of about 149.60 million kilometers every 365.26 Earth days.
a) To determine the Earth’s average orbital speed, we will make use of the below formula to calculate angular speed
W = 2/T
W = (2 x 3.143) / (365.26 x 24)
W = 6.283 / 876624
W = 7.2 x Rad/hr
The Earth’s average orbital speed V = Wr
V = 7.2 x x 149.6 x
V = 107225.5 kilometers per hours.
b) Based on the information given in this question, to calculate the approximate mass of the Sun, we will use Kepler's 3rd law
M = (4) / G
M = (4 x 9.8696 x 3.35 x ) / (6.67 x
x 7.68 x
<em>)</em>
<em>M = 1.32 x </em> / 51.226
M = 2.58 x Kg
Therefore, the Earth’s average orbital speed expressed in kilometers per hours is 107225.5 Km/hr and the mass of the sun is 2.58 x Kg
Learn more about Orbital Speed here: brainly.com/question/22247460
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