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vesna_86 [32]
3 years ago
15

Imagine that there is a small rocky body caught by Earth’s gravity. Draw a comic-strip cartoon to illustrate its journey as it t

ravels through space toward Earth, enters Earth’s atmosphere, and lands on Earth. Describe your illustration with narration or speech/thought bubbles. Include the use of these key terms: atmosphere, meteor, meteoroid, meteorite.
Physics
1 answer:
Harlamova29_29 [7]3 years ago
8 0

Answer:

To create this comic strip you can use a narration describing each step and illustrate each one with one image or drawing.

Creating a comic strip involves using images and short texts to explain a specific idea or phenomenon. In the case of the process for a meteor to enter Earth you can use the following ideas.

A meteoroid approaches the Earth at high speed and draw a meteor traveling near to different planets and approaching Earth.

What is that? and draw the Earth wondering who or what is approaching.

The meteoroid enters the atmosphere of the Earth and becomes a meteor and draw the rocky body burning

The rocky body crashes with the surface becoming a meteorite and draw the zone where the meteorite crashed.

Explanation:

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Answer:

a=9\ cm/s^2

Explanation:

<u>Average Acceleration </u>

Acceleration is a physical magnitude defined as the change of velocity over time. When we have experimental data, we can compute it by calculating the slope of the line in velocity vs time graph.

Note: <em>We cannot see if the time axis is numbered in increments of 1 second, and we'll assume that. </em>

When t_2=4\ sec, the graph shows a value of v_2=36\ cm/s

When t_1=0\ sec, the object is at rest, v_1=0

We compute the average acceleration as

\displaystyle a=\frac{v_2-v_1}{t_2-t_1}

\displaystyle a=\frac{36\ cm/s-0\ cm/s}{4\ sec-0\ sec}

\displaystyle a=\frac{36\ cm/s}{4\ s}

\boxed{a=9\ cm/s^2}

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A proton moves through a magnetic field at 20.3 % of the speed of light. At a location where the field has a magnitude of 0.0062
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Force on the proton is equal to F=qvBsin\Theta =1.6\times 10^{-19}\times 6.9\times 10^7\times 0.00629\times sin(137^{\circ})=4.73\times 10^{-14}N

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