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Lilit [14]
2 years ago
12

Line segments A prime B prime and A B. The distance from the center of dilation P to A prime is 3. The distance from P to A is 5

.
1/2
3/5
1 2/3
2
HURRY I HAVE !0 MINS LEFT

Mathematics
1 answer:
OverLord2011 [107]2 years ago
8 0
The answer is P to A prime is 3 I think

Good luck!
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3 0
3 years ago
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Find the slope and the equation please<br><br>and step by step PLEASE.​
Svetllana [295]

Answer:

y = \frac{-4}{5}x + 1

Step-by-step explanation:

Slope is rise over run, or the vertical progression over the horizontal progression.

Your example has a line that heads downwards, so we know that the slope is negative. If we count the squares, the "rise" is down by 4. We count the squares going horizontally and there are 5. So, your slope is \frac{-4}{5}.

The other half of the equation is the y-intercept, or where the line crosses the y axis. It appears to be at (0 , 1), so we can say that your y-intercept is 1.

5 0
3 years ago
22 less than 5 times a number f
olya-2409 [2.1K]

Answer:

5f - 22

Step-by-step explanation:

pls igve brainliest

8 0
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1. D=5.9 ft.
Shtirlitz [24]

\qquad\qquad\huge\underline{{\sf Answer}}♨

Here's the solution ~

As we know, we can calculate the circumference of a circle in terms of its diameter as :

\qquad \sf  \dashrightarrow \:c =  \pi d

where, c = circumference and d = diameter

And also, circumference of circle is terms of radius (r) is :

\qquad \sf  \dashrightarrow \:c =  2\pi r

Now, let's move on to questions ~

<h3>First </h3>

\qquad \sf  \dashrightarrow \:3.14 \times 5.9

\qquad \sf  \dashrightarrow \: \approx18.53 \: ft

<h3 />

・ .━━━━━━━†━━━━━━━━━.・

<h3>Second</h3><h3 /><h3 /><h3 /><h3>\qquad \sf  \dashrightarrow \:3.14 \times 3.2</h3>

\qquad \sf  \dashrightarrow \: \approx10.048 \: ft

・ .━━━━━━━†━━━━━━━━━.・

<h3>Third</h3>

\qquad \sf  \dashrightarrow \:3.14 \times 6.1

\qquad \sf  \dashrightarrow \: \approx19.15 \: ft

・ .━━━━━━━†━━━━━━━━━.・

<h3>Fourth</h3>

\qquad \sf  \dashrightarrow \:2×3.14 \times  3.7

\qquad \sf  \dashrightarrow \: \approx2×11.62  \: m

\qquad \sf  \dashrightarrow \: \approx23.24  \: m

・ .━━━━━━━†━━━━━━━━━.・

<h3>Fifth </h3>

\qquad \sf  \dashrightarrow \:2×3.14 \times  6.2

\qquad \sf  \dashrightarrow \: \approx2× 19.47 \: units

\qquad \sf  \dashrightarrow \: \approx38.94  \: m

・ .━━━━━━━†━━━━━━━━━.・

<h3>Sixth</h3>

\qquad \sf  \dashrightarrow \:2×3.14 \times  5.1

\qquad \sf  \dashrightarrow \: \approx2×16.01 \: ft

\qquad \sf  \dashrightarrow \: \approx \: 32.02m

➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖

7 0
2 years ago
Find the distance between the points (1,3) and (5,0).
Irina18 [472]

distance between two points is [(x2-x1)^2 +(y2-y1)^2]^1/2

I.e,[{5-1)^2+(0-3)^2]^1/2

[16+9]^1/2

[25]^1/2

5

5 0
3 years ago
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