The given magnitude and direction of and , can be
expressed in terms of unit vectors, to give - .
Correct response:
- The component form of is
- The magnitude of is <u>1117.47 meters</u>
<h3>Which is the method used to find the displacement vector?</h3>
<em>The possible parameters obtained from a similar question posted online are;</em>
Magnitude of = 360 m
Direction of = 40° above the horizon
Magnitude of = 880 m
Direction of = Another 123° from
Required:
The displacement of the airplane, while the radar was tracking it, = -
Solution;
= 360 × cos(40°)· + 360 × sin(40°)·
= 880 × cos(123° + 40°)· + 880 × sin(123° + 40°)·
Which gives;
= (880 × cos(163°) - 360 × cos(40°))· + ((880 × sin(163°) - 360 × cos(40°))·
Which gives;
Therefore;
- In terms of unit vectors is, =
The magnitude of ≈ √((-1117.32)² + (-18.49)²) ≈ 1117.47
- Which gives the magnitude of the displacement, of the airplane is approximately <u>1117.47 meters</u>
Learn more about vectors here:
brainly.com/question/24855749