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Sunny_sXe [5.5K]

3 years ago

10

Dense fluids exert___________buoyant force then less dense fluids because they have more mass within a certain volume than a les

s dense fluid.

1 answer:

sergij07 [2.7K]3 years ago

6 0

Answer:

The answer is 'more' as more mass can exert more pressure

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Caca box like fish no earnings play like caca

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I actually have 20000 arena points thank you very much

6 0

3 years ago

Read 2 more answers

a dragster gets to a peed of 112m/s over a distance of 300m from rest. Determine the acceleration of the dragster.

madreJ [45]

A dragster gets to a speed of 112 m/s over a distance of 300 m from the rest, then the acceleration will be 20.9 m/s².

<h3>What is Acceleration?</h3>

The rate of change in an object's velocity with respect to time is known as acceleration in mechanics. The vector quantity of accelerations. The direction of the net force that is acting on an object determines its acceleration.

Since acceleration has both a magnitude and a direction, it is a vector quantity. Velocity is a vector quantity as well. The definition of acceleration is the change in velocity vector over a time interval divided by the time interval.

According to the question, the given values are :

Final velocity, v = 112 m/s.

Initial velocity, u = 0 m/s

Distance, s = 300 m.

Use the equation of motion,

v² - u² = 2as

112 ² - 0 = 2 (a)(300)

a = 12544/600

a = 20.9 m/s².

Hence, the acceleration of the dragster will be 20.9 m/s².

To get more information about Acceleration :

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3 0

1 year ago

Challenge: Determine the speed of the waves at each tension setting (high, medium and low). Explain what measurements you made t

Svetradugi [14.3K]

Answer:

high tension: 4.2 × 1.5 = 6.3 cm/s

medium tension: 2.8 ×1.5 = 4.2 cm/s

low tension: 0.8 × 1.5 = 1.2 cm/s

Explanation: Given Settings:

amplitude: 0.75 cm

damping: zero

Using

Speed = frequency ×wavelength

Where

Wavelength = 0.75 × 2 = 1.5 cm

Therefore:

high tension: 4.2 × 1.5 = 6.3 cm/s

medium tension: 2.8 ×1.5 = 4.2 cm/s

low tension: 0.8 × 1.5 = 1.2 cm/s

4 0

3 years ago

if you have a block of steel with a density of 7.8g/cm3 and a block of gold with a density of 19.3g/cm3 each with the same volum

natita [175]

Gold because 19.3 is greater than 7.8

3 0

3 years ago

I NEED HELP ASAP! BRAINIEST TO THE CORRECT ANSWER. HELP ME NOW!

sergij07 [2.7K]

Answer:

<h3>a)</h3>

$\boxed{\mathfrak{Power(P)=\frac{Voltage(V)^2}{Resistance(R)} }}$

V = 12 V
P = 24 W

$\implies \mathsf{24=\frac{12^2}{R} }$

$\implies \mathsf{24R=12^2 }$

$\implies \mathsf{24R=144 }$

<u>=> R= 6 Ohms(Ω)</u>

<h3>b)</h3>

$\boxed{\mathfrak{Power(P)=\frac{Voltage(V)^2}{Resistance(R)} }}$

Power (P)= 100 W

<em>these lights operate at the usual 240 volts direct from the main electricity supply. Therefore,</em>

V = 240 V

$\implies \mathsf{100=\frac{240^2}{R} }$

<em>R and 100 can interchange places</em>

$\implies \mathsf{R=\frac{240^2}{100} }$

$\implies \mathsf{R=\frac{57600}{100} }$

<u>=> R = 576 Ω</u>

<u></u>

By Ohm's Law:

$\boxed{\mathsf{Voltage(V)=Current(I) \times Resistance(R)}}$

=> 240 = I × 576

=>

=> I = 0.417 A

<h3 /><h3>c)</h3>

I don't know it's resistance,... so sorry

<h3>d)</h3>

The brightness of the bulb in series is <em><u>less than</u></em> when they're placed individually.

For bulbs in series their resistance gets added to form the equivalent resistance of the two bulbs.

Their resistances are nothing but mere numbers and the sum of two numbers(positive of course) is greater than the numbers.

So, the effective resistance of some bulbs in series <u>is more</u> than the individual resistance.

And

<em>Brightness, i. e., Power</em>

$\boxed{\mathfrak{Power \propto \frac{1}{Resistance} }}$

If resistance increases, Power decreases.

Here, the effective resistance was for sure larger, therefore resistance was increasing, hence power decreased taking brightness along with it.

3 0

3 years ago