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Stella [2.4K]
3 years ago
15

How strong is a tesla and how strong is a newton?

Physics
1 answer:
krok68 [10]3 years ago
8 0
-- "Tesla" is a unit for the strength of a magnetic field.

The Earth's magnetic field at the surface ... the one that makes
compasses work ... averages roughly 45 microteslas. 

So 1 Tesla = somewhere around 20,000 times the magnitude
of Earth's magnetic field at the surface.

There's a smaller, more convenient unit, called the 'Gauss'.
1 Tesla = 10,000 Gauss.  The Earth's magnetic field ranges
between 0.25 to 0.65 Gauss at various places on the surface.


-- Newton is a unit of force, equal to about 3.6 ounces. 
1 pound of force is about 4.45 newtons.
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You can calculate acceleration with the following equation: Acceleration = (final velocity - starting velocity) ÷ time it takes
Whitepunk [10]

Answer:

1000m/s²

Explanation:

Given parameters:

Initial velocity  = 6000m/s

Final velocity  = 11000m/s

Time  = 50s

Unknown:

Acceleration of the plane  = ?

Solution:

Acceleration is the rate of change of velocity with time:

    Acceleration = (final velocity - starting velocity) ÷ time

Therefore;

      Acceleration  = \frac{11000 - 6000}{5}   = 1000m/s²

7 0
3 years ago
A 14.0 g wad of sticky clay is hurled horizontally at a 110 g wooden block initially at rest on a horizontal surface. The clay s
ahrayia [7]

Answer:

86.53 m/s

Explanation:

Given:

Mass of clay (m) = 14.0 g = 0.014 kg

Mass of block (M) = 110 g = 0.110 kg

Initial speed of block (U) = 0 m/s

Sliding distance (d) = 7.50 m

Coefficient of friction between block and surface (μ) = 0.650

Let the initial speed of clay be 'u' and speed of clay and block just after collision be 'v'.

Now, momentum is conserved just before and just after collision.

Momentum just before collision = mu + 0 = mu

Momentum just after collision = (m + M)v

Therefore, mu=(M+m)v --------- (1)

Now, using newton's second law and we find the acceleration of the system.

The frictional force is given as:

f=\mu mg=-ma\\\\a=-\mu g

Now, using equation of motion, we can find the velocity just after collision.

0^2=v^2+2ad\\\\v=\sqrt{-2ad}\\\\v=\sqrt{-2\times (-\mu g)\times d}\\\\v=\sqrt{2\mu gd}

Plug in the given values and find 'v'. This gives,

v=\sqrt{2\times 0.650\times 9.8\times 7.50}\\\\v=\sqrt{95.55}=9.77\ m/s

Now, using equation (1) and substituting the given values, we get:

0.014u=(0.014+0.110)\times 9.77\\\\u=\frac{0.124\times 9.77}{0.014}\\\\u=86.53\ m/s

Therefore, the speed of the clay immediately before impact is 86.53 m/s.

7 0
4 years ago
Which one of the following types of electromagnetic radiation causes certain substances to fluoresce?
nalin [4]
The answer is D. <span>Uv causes more stuff to fouresce </span>
8 0
3 years ago
When the magnetic flux through a coil of wire changes, what is generated between the ends of the coil
Gnesinka [82]
When a magnet is moved into a coil of wire, changing the magnetic field and magnetic flux through the coil, a voltage will be generated in the coil according to Faraday's Law.
4 0
3 years ago
Gold is the most ductile of all metals. For example, one gram of gold can be drawn into a wire 2.05 km long. The density of gold
arsen [322]

Answer:

Resistance of gold wire, R=1977 \times 10^3 ohm

Explanation:

In this question we have given

Density of gold, d=19.3\times 10^3 \frac{kg}{m^3}

resistivity of gold, r=2.44\times 10^{-8} ohm.m

Length of wire, L= 2.05 km

Temperature, T= 20^oC

We know that relation between volume and density is given as

Density= \frac{mass}{Volume}

Therefore, volume occupied by one gram gold is given as,

V=\frac{.001 kg}{19.3\times 10^3 Kg m^{-3}} = 5.181\times 10^{-8} m^3.........(1)

We Know that Volume of gold wire which is cylindrical in shape is given by following formula

V=\pi \times r^2 \times L......(2)

Here,

A= \pi \times r^2...........(3)

here A is the cross sectional area of cylendrical gold wire  

From equation 2 and 3

we got

V=A \times L...............(4)

on comparing equation 1 and equation 4, we got,

A \times L=5.181\times 10^{-8} m^3

A=\frac{5.181\times 10^{-8} m^3}{2050 m}

A=2.53\times 10^{-11}m^2

we know that resistance and resistivity are related by following formula,

Resistance = resistivity\times \frac{L}{A}................(5)

Put values of resistivity, A and L in equation 5, we got

R = \frac{2.44 \times 10^{-8} ohm.m \times 2050 m}{2.53\times 10^{-11} m^2}

R=1977 \times 10^3 ohm

Therefore resistance of gold wire, R=1977 \times 10^3 ohm

7 0
3 years ago
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