Noble gas configuration for Li : [He]2s¹
<h3>Further explanation
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In an atom, there are levels of energy in the shell and sub-shell
This energy level is expressed in the form of electron configurations.
Lithium with atomic number 3, then the electron configuration:
1s²2s¹
And for noble gas configuration or it can be called Condensed electron configurations :
[He]2s¹
Answer:
jet stream
Explanation:
Jet streams or air jets are wind currents that move the planet from west to east at high altitudes in a wavy pattern. Among the most powerful jets are the polar jets, which occur around 7 and 12 km altitude, between latitudes 30 ° to 60 °. The width of a jet stream is a few hundred kilometers, while its vertical thickness is no more than 5 km. Jet currents can also be defined as a fast moving air range that moves from west to east, high in the atmosphere. This air stream constantly bends and descends to move climate systems.
Enriched uranium is a type of uranium in which the percent composition of uranium-235 has been increased through the process of isotope separation. Natural uranium is 99.284% 238U isotope, with 235U only constituting about 0.711% of its mass. ... The term oralloy is still occasionally used to refer to enriched uranium. Hope this helps
Answer:
Explanation:
The density of a gas can be obtained using the gas ideal equation and the molar mass of the gas.
This is the decution of the final formula:
Now, you just need to substitute values:
- R = 0.08206 atm-liter / k-mol
- d = 32.0 g/mol × 0.9869 atm / [0.08206 atm-liter/k-mol × 273.15K]
- d = 1.4 g/liter (using two significant figures)
As you see, I have not used the 4.8 grams datum. That is because the density of the gases may be calculated from the temperature, pressure and molar mass of the gas, using the ideal gas equation.
Since, you have the mass of gas, you might use this other procedure:
- Volume of 1 mol of gas at STP: about 22.4 liter/mol
- Mass of 1 mol of oxygen gas: 32.0 g/mol (the molar mass)
- number of moles in 4.8 g of oxygen = 4.8 g / 32.0 g/mol = 0.15 mol
- Volume of 0.15 mol of oxygen: 0.15 mol × 22.4 liter/mol = 3.36 liter
- Density = mass / volume = 4.8 g / 3.36 liter = 1.4 g/liter (same result)