How many significant figures are in the following number? 5.67 x 106<br> 3<br> 4<br> 5<br> 6

The mass of a dust particle would be measured in?

Delicious77 [7]

A dust particle with mass of 0.050 and a charge

5 0

2 years ago

Which physical method can be used for obtaining a sample of salt from a sm

lana [24]

The physical method that can be used for obtaining a sample of salt from a small beaker of salt and water would be evaporation.

<h3>Separation of salt and water</h3>

A mixture of salt and water can be separated by a method known as evaporation. This is based on the assumption that the salt in question is a water-soluble salt.

In order to separate the salt/water mixture:

Place the mixture in a suitable evaporating dish
Boil the mixture until all the water evaporates.
The remaining residue would be the salt

Care should be taken not to overheat the residue in order to avoid melting. Evaporation is generally used to separate a mixture of water and soluble salt. If the salt is insoluble, filtration using a suitable filter paper will filter off the salt while the water is collected as the filtrate.

More on evaporation can be found here: brainly.com/question/1097783

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Which physical method can be used for obtaining a sample of salt from a small beaker of salt water?

6 0

1 year ago

In atmospheric chemistry, the following chemical reaction converts SO2, the predominant oxide of sulfur that comes from combusti

Misha Larkins [42]

Answer:

Explanation:

From the given information;

The chemical reaction can be well presented as follows:

$\mathtt{SO_{2(g)} + \dfrac{1}{2}O_{2(g)} }$ ⇄ $\mathtt{3SO_{2(l)}}$

Now, K is known to be the equilibrium constant and it can be represented in terms of each constituent activity:

i.e

$K = \dfrac{a_{so_3}}{a_{so_2} a_{o_2}^{\frac{1}{2}}}$

However, since we are dealing with liquids solutions;

$K = \dfrac{1}{\dfrac{Pso_2}{P^0}\Big ( \dfrac{Po_2}{P^0} \Big)^{1/2}}$ since the activity of $a_{so_3}$ is equivalent to 1

Hence, under standard conditions(i.e at a pressure of 1 bar)

$K = \dfrac{1}{Pso_2Po_2^{1/2}}$

(b)

From the CRC Handbook, we are meant to determine the value of the Gibb free energy by applying the formula:

$\Delta _{rxn} G^o = \sum \Delta_f \ G^o (products) - \sum \Delta_fG^o (reactants) \\ \\ = (1) (-368 \ kJ/mol) - (\dfrac{1}{2}) (0) - ((1) (-300.13 \ kJ/mol)) \\ \\ = -368 \ kJ/mol + 300.13 \ kJ/mol \\ \\ \simeq -68 \ kJ/mol$

Thus, for this reaction; the Gibbs frree energy = -68 kJ/mol

(c)

Le's recall that:

At equilibrium, the instantaneous free energy is usually zero &

Q(reaction quotient) is equivalent to K(equilibrium constant)

So;

$\mathtt{\Delta _{rxn} G = \Delta _{rxn} G^o + RT In Q}$

$\mathtt{0- \Delta _{rxn} G^o = RTIn K } \\ \\ \mathtt{ \Delta _{rxn} G^o = -RTIn K } \\ \\ K = e^{\dfrac{\Delta_{rxn} G^o}{RT}} \\ \\ K = e^{^{\dfrac{67900 \ J/mol}{8.314 \ J/mol \times 298 \ K}} }$

$K =7.98390356\times 10^{11} \\ \\ \mathbf{K = 7.98 \times 10^{11}}$

(d)

The direction by which the reaction will proceed can be determined if we can know the value of Q(reaction quotient).

This is because;

If Q < K, then the reaction will proceed in the right direction towards the products.

However, if Q > K , then the reaction goes to the left direction. i.e to the reactants.

So;

$Q= \dfrac{1}{Pso_2Po_2^{1/2}}$

Since we are dealing with liquids;

$Q= \dfrac{1}{1 \times 1^{1/2}}$

Q = 1

Since Q < K; Then, the reaction proceeds in the right direction.

Hence, SO2 as well O2 will combine to yield SO3, then condensation will take place to form liquid.

8 0

3 years ago

Write balanced complete ionic equation for hcl(aq)+lioh(aq)→h2o(l)+licl(aq) express your answer as a chemical equation. identify

Svet_ta [14]

Explanation:

An equation is said to be balanced when the number of atoms on both reactant and product side are equal in number.

Whereas an equation where electrolytes in an aqueous solution are represented as dissociated ions is known as an ionic equation.

For example, $HCl(aq) + LiOH(aq) \rightarrow H_{2}O(l) + LiCl(aq)$ can be represented in ionic form as follows.

$H^{+} + Cl^{-} + Li^{+} + OH^{-} \rightarrow H_{2}O(l) + Li^{+} + Cl^{-}$

Now, cancelling the common ions present on both sides of the equation. The resulting, ionic equation will be as follows.

$H^{+} + OH^{-} \rightarrow H_{2}O(l)$

8 0

3 years ago

Read 2 more answers

Arrange the following set of atoms in order of decreasing atomic size: Sn, I, Sr

vampirchik [111]

Atomic size
Sr>Sn>I

A)
B)

3 0

3 years ago

How many significant figures are in the following number? 5.67 x 106 3 4 5 6