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3 years ago

What is the molar mass of CH20?

Chemistry

1 answer:

cluponka [151]3 years ago

4 0

Answer:

30.026 <em>g/mol</em>

Explanation:

no explaination

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Please help with the equation in picture

matrenka [14]

Maybe 47.999 g if I can’t I’m sorry.

5 0

3 years ago

Calculate the enthalpy of the reaction 4B(s)+3O2(g)→2B2O3(s) given the following pertinent information: B2O3(s)+3H2O(g)→3O2(g)+B

Ivenika [448]

Answer:

-2546 kJ

Explanation:

It is possible to obtain the enthalpy of a reaction from the sum of different intermediate reactions.

For the reaction:

4B(s) + 3O₂(g) → 2B₂O₃(s)

The intermediate reactions are:

A- B₂O₃(s) + 3H₂O(g) → 3O₂(g) + B₂H₆(g), ΔH°A= +2035 kJ

B- 2B(s) + 3H₂(g) → B₂H₆(g), ΔH°B= +36 kJ

C- H₂(g) + 1/2O₂(g) → H₂O(l), ΔH°C= -285 kJ

D- H₂O(l) → H₂O(g), ΔH°D= +44 kJ

2B = 4B(s) + 6H₂(g) → 2B₂H₆(g) ΔH°2B= +78 kJ

-2A = 6O₂(g) + 2B₂H₆(g) → 2B₂O₃(s) + 6H₂O(g) ΔH°-2A= -4070 kJ

-6C = 6H₂O(l) → 6H₂(g) + 3O₂(g) ΔH°-6C= +1710 kJ

-6D = 6H₂O(g) → 6H₂O(l) ΔH°-6D = -264 kJ

The sum of 2B - 2A - 6C - 6D produce:

4B(s) + 3O₂(g) → 2B₂O₃(s)

And the enthalpy is: ΔH°2B + ΔH°-2A + ΔH°-6C + ΔH°-6D = <em>-2546 kJ</em>

I hope it helps!

3 0

3 years ago

Calculate the density of an object with a mass of 3.8 g, that when placed in a 10.0 mL graduated cylinder with an initial volume

Arturiano [62]

Answer : The density of an object is 0.93 g/mL

Explanation : Given,

Mass of an object = 3.8 g

Initial volume = 4.5 mL

Final volume = 8.6 mL

First we have to calculate the volume of an object.

Volume of an object = Final volume - Initial volume

Volume of an object = 8.6 mL - 4.5 mL

Volume of an object = 4.1 mL

Now we have to calculate the density of an object.

Formula used:

$\text{Density}=\frac{\text{Mass of an object}}{\text{Volume of an object}}$

Now putting all the given values in this formula, we get:

$\text{Density}=\frac{3.8g}{4.1mL}$

$\text{Density}=0.93g/mL$

Therefore, the density of an object is 0.93 g/mL

3 0

3 years ago

Which conclusion could be made from Ernest Rutherford’s gold foil experiment ?

mote1985 [20]

From the Rutherford's gold foil experiment one can conclude that nucleus was very small in size, as compared to the atoms. In the experiment Rutherford discovered that, the atom contains a very small nucleus where all of its positive charge of the atom is present.

3 0

4 years ago

PLZ HELP (SCIENCE) Match the following items.

FromTheMoon [43]

Oxidation: a chemical change resulting form a reaction with oxygen
Endothermic:a reaction that takes in energy
Exothermic: a reaction that releases energy
Decomposition:chemical change whereby a molecule breaks down into simpler moles clues or elements
Subscript:written underneath or below

6 0

2 years ago

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