a bus makes a stop at 2:30,letting off 15 people and letting on 9.The bus makes another stop ten minutes later to let off 4 more
1 answer:
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Answer:
a)0.6192
b)0.7422
c)0.8904
d)at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.
Step-by-step explanation:
Let z(p) be the z-statistic of the probability that the mean price for a sample is within the margin of error. Then
z(p)= where
- Me is the margin of error from the mean
- s is the standard deviation of the population
- N is the sample size
a.
z(p)= ≈ 0.8764
by looking z-table corresponding p value is 1-0.3808=0.6192
b.
z(p)= ≈ 1.1314
by looking z-table corresponding p value is 1-0.2578=0.7422
c.
z(p)= ≈ 1.6
by looking z-table corresponding p value is 1-0.1096=0.8904
d.
Minimum required sample size for 0.95 probability is
N≥ where
- N is the sample size
- z is the corresponding z-score in 95% probability (1.96)
- s is the standard deviation (50)
- ME is the margin of error (8)
then N≥ ≈150.6
Thus at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.
Answer:
Option (3)
Step-by-step explanation:
Properties for the vertical stretch or shrink of a function,
If a function is f(x) = k|x|
1). Function will be vertically stretched if k > 1
2). Function will have a vertical shrink if 0 < k < 1
To fit the given data graph of f(x) = |x| will vertically shrink without any translation along x or y-axis.
And the value of k will be, 0 < k < 1.
Therefore, g(x) = will be the transformed graph.
Therefore, Option (3) will be the correct option.