Since the pressure is constant, you can use the equation V₁/T₁=V₂/T₂ and solve for T₂. (T₂=(T₁/V₁)V₂)
since this is a gas law type question, the temperatures need to be in kelvin therefore you need to convert 15°C to kelvin. 15°C+273=288K. The volume are already in L so they don't have to be converted.
now you just need to plug everything in:
T₂=(288K/99L)x1200L
T₂=3491K
The answer is you need if you have a 99L of gas at 288K, you have to increase the temperature to 3491K to get a volume of 1200L if the pressure remains constant.
I hope this helps. Let me know in the comments if anything is unclear.
Answer:
The temperature in Celsius is 383, 7°C
Explanation:
We use the formula PV=nRT. We convert the pressure in KPa into atm:
101,325kPa---1 atm
114kPa--------x=(114kPa x 1 atm)/101,325kPa=1, 125 atm
PV=nRT ---> T= PV/nR
T=1, 125 atm x 35, 9 L/ 0,750 mol x 0,082 l atm/K mol
T= 656, 7 K
0°C= 273K---> 656,7 -273K= <em>383,7°C</em>
Weak Bonds
These bases contain Nitrogen and these create a twofold strand of DNA through not so strong hydrogen bonds. The nitrogen bases, notwithstanding, have particular shapes and hydrogen bond properties so guanine and cytosine just bond with each other, while adenine and thymine additionally bond only. This matching off of the nitrogen bases is called complementarity. All together for hydrogen clinging to happen by any means, a hydrogen bond benefactor must have a corresponding hydrogen bond acceptor in the base opposite it.
Answer:
a. 1/3
In the picture- D. 4
Explanation:
The product of the gradients of perpendicular lines =-1
m1m2=-1
Given an equation of a line in the form y=mx+c, m is the gradient of the line.
For y= -3x-9, m=-3
m1m2=-1
-3×m2=-1
m2=1/3
The gradient of the perpendicular line is 1/3
For the question in the picture, y=-1/4x-9, m=-1/4
m1×m2=-1
-1/4m2=-1
m2=4
The slope of the line perpendicular to y=-1/4x-9 is 4