All categories

2 years ago

How do I find molar mass

1 answer:

7 0

Answer:The molar mass is the mass of a given chemical element or chemical compound (g) divided by the amount of substance (mol).

The molar mass of a compound can be calculated by adding the standard atomic masses (in g/mol) of the constituent atoms.

Explanation:

You might be interested in

Compare the modern (electron cloud) model of the atom with Bohr’s atomic model. Which of these statements describe the two model

AfilCa [17]

Answer:

B. Bohr’s model electrons cannot exist between orbits, but in the electron cloud model, the location of the electrons cannot be predicted.

AND

C. The modern model explains all available data about atoms; Bohr’s model does not.

Explanation:

The answers are right on Edge. :)

6 0

3 years ago

Read 2 more answers

How many grams of magnesium nitride is required to produce 25.00 g of magnesium hydroxide?

Lesechka [4]

Answer:

25 grams of Mg(OH)2 will be produced by 14.424 gram of Mg3N2

Explanation:

The balanced equation is

Mg3N2 + 6H2O -> 3Mg(OH)2 + 2NH3

Molecular weight of magnesium nitride = 100.9494 g/mol

Molecular weight of magnesium hydroxide = 58.3197 g/mol

one mole of Mg3N2 produces three moles of 3Mg(OH)2

100.9494 g/mol of Mg3N2 produces 3* 58.3197 g/mol of Mg(OH)2

1 gram of Mg3N2 produces

$\frac{3* 58.3197}{100.9494 } \\1.733$ grams of Mg(OH)2

Or 1.733 grams of Mg(OH)2 will be produced by 1 gram of Mg3N2

25 grams of Mg(OH)2 will be produced by 14.424 gram of Mg3N2

6 0

2 years ago

At 35 C, a sample of gas has a volume of 256 ml and a pressure of 720.torr. What would the volume

Natalija [7]

Answer: Volume would be 196.15 mL if the temperature were changed to $22^{o}C$ and the pressure to 1.25 atmospheres.

Explanation:

Given: $T_{1} = 35^{o}C = (35 + 273) K = 308 K$ , $V_{1}$ = 256 mL,

$P_{1}$ = 720 torr (1 torr = 0.00131579 atm) = 0.947368 atm

$T_{1} = 22^{o}C = (22 + 273) K = 295 K$ , $P_{2} = 1.25 atm$

Formula used to calculate volume is as follows.

$\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}$

Substitute the values into above formula as follows.

$\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\frac{1 atm \times 256 mL}{308 K} = \frac{1.25 atm \times V_{2}}{295 K}\\V_{2} = 196.15 mL$

Thus, we can conclude that the volume would be 196.15 mL if the temperature were changed to $22^{o}C$ and the pressure to 1.25 atmospheres.

4 0

2 years ago

What is the molar mass of AgF. 51.9g/mol 198.8g/mol 126.87g/mol 99.7g/mol

lisov135 [29]

Just find Ag and F on periodic table, find g/mol for each one and add them together

3 0

3 years ago

I'm stuck on this assignment, +20 PTS and BRAINLIEST for step by step:

dolphi86 [110]

Answer:

2. 2.74 L

3. 488 K

4. 7.47 L

5. 38.6 L

6. 2.85 mol

7. 319 K

8. 3.43 kPa

Explanation:

Generally speaking, you want to convert units to SI units, but in this case, we are working with ratios. This makes up for using the units that wouldn't appropriate elsewhere.

2. Use the equation P₁V₁ = P₂V₂. Solve for V₂.

(3.05 L)(870 kPa) = (969 kPa)(V₂)

V₂ = 2.74 L.

3. Use the equation V₁/T₁ = V₂/T₂. Solve for T₂.

(3.32 L)/(360 K) = (4.50 L)/(T₂)

T₂ = 488 K.

4. Do the same as above, but for V₂.

(5.10 L)/(-56°C) = V₂/(-82°C)

V₂ = 7.47 L

5. Use the equation V₁/n₁ = V₂/n₂. Solve for V₂.

(37.2 L)/(0.750 mol) = (V₂)/(0.778 mol)

V₂ = 38.6 L

6. Do the same as above, but for n₂.

(86.0 L)/(2.65 mol) = (92.5 L)(n₂)

n₂ = 2.85 mol

7. Use the equation P₁/T₁ = P₂/T₂. Solve for T₂.

(3.00 atm)/(390 K) = (2.45 atm)/(T₂)

T₂ = 319 K

8. Do the same as above, but for P₂.

In this specific case, however you will need to convert units. Since both temperatures don't have the same sign, the ratio won't come out right. Convert to Kelvin. Add 273.15 to the temperature in Celsius to convert to Kelvin -12.3°C = 260.85 K 25°C = 298.15 K.

(3.00 kPa)/(260.85 K) = P₂/(298.15 K)

P₂ = 3.43 kPa

There is a lot in here... If you are confused about something, let me know!

6 0

3 years ago

How do I find molar mass​

How do I find molar mass