Answer:
a. Rate constant: 1.2118x10⁻⁴ yrs⁻¹
b. The age of the object is 20750 years
Explanation:
a. We can solve the rate constant in an isotope decay by using Half-Life, as follows:
K = Ln 2 / Half-life
K = ln 2 / 5720 years =
<h3>1.2118x10⁻⁴ yrs⁻¹</h3><h3 />
b. The general equation of isotope decay is:
Ln [A] = -kt + Ln [A]₀
<em>Where [A] is concentration of the isotope after time t, </em>
<em>k is rate constant</em>
<em>and [A]₀ initial concentration of the isotope.</em>
<em />
Computing the values of the problem:
Ln [0.89x10⁻¹⁴] = -1.2118x10⁻⁴ yrs⁻¹t + Ln [1.1x10⁻¹³]
-2.5144 = -1.2118x10⁻⁴ yrs⁻¹t
20750 years = t
The age of the object is 20750 years
<em />
Answer:
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Answer:
There will be 0.825 grams of CO2 produced
Explanation:
Step 1: Data given
Mass of water formed = 0.45 grams
Molar mass of water = 18.02 g/mol
Molar mass of CO2 = 44.01 g/mol
Step 2: The balanced equation
C3H8 + 5O2 → 4H2O + 3CO2
Step 3: Calculate moles of water
Number of moles water = mass of water / molar mass water
Number of moles water = 0.45 grams / 18.02 g/mol
Number of moles water = 0.025 moles
Step 4: Calculate moles of CO2
For 1 mol of propane we need 5 moles of O2 to produce 4 moles of H2O and 3 moles of CO2
When 0.025 moles of H2O are produced, we'll get 3/4 * 0.025 = 0.01875 moles of CO2 produced
Step 5: Calculate mass of CO2 produced
Mass of CO2 = moles of CO2 * molar mass of CO2
Mass of CO2 = 0.01875 moles * 44.01 g/mol
Mass of CO2 = 0.825 grams
There will be 0.825 grams of CO2 produced
I think there is 3 moles of carbon atoms in 3 moles of methane. This is so as the chemical formula for methane is CH4, which means that for every 1 mole of methane molecule you have 1 mole of carbon atom as in each molecule of methane there's one carbon atom.
After a Rainstorm the puddle than starts to evaporate. Going into the air as the water vapor turns from liquid to gas as they begin to form a cloud it repeats the cycle again but there is more to the water cycle but that’s a simple answer for your question.