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FrozenT [24]
4 years ago
16

The amount of energy required to break a nucleus into individual protons and neutrons is called

Physics
2 answers:
mario62 [17]4 years ago
7 0

Answer: Binding energy

Explanation:

The amount of energy required to break a nucleus into individual protons and neutrons is called Binding energy. Binding energy holds the nucleons in the nucleus. It is equal to mass defect. In  creation of a bound system, energy or equivalent mass is released.

kompoz [17]4 years ago
5 0

Question: The amount of energy required to break a nucleus into individual protons and neutrons is called

Answer: binding energy

Explanation: the energy holds a nucleus together

question answered by

(jacemorris04)

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Complete the table
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Answer: the second one

Explanation:

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3 years ago
The uncertainty principle applies not only to momentum and position, but also to energy and time.
Elan Coil [88]

Answer:

(a)    that is a true statement

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For the following types radio waves infared radiation visible light ultraviolet radiation gamma radiation of electromagnetic rad
ddd [48]

Answer: Option 5.

Decreases increases increases.

Explanation:

Electromagnetic spectrum refers to differences in frequencies, wavelengths and photon energies of electromagnetic radiation.

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The electromagnetic radiations : radio waves, microwaves, infrared, visible light, ultraviolet, X-rays, and gamma rays have high-frequency and short wavelengths. Their wavelengths decrease. The photon energy is directly proportional to wave frequency.

6 0
4 years ago
The tub of a washer goes into its spin-dry cy-cle, starting from rest and reaching an angularspeed of 3.1 rev/s in 10.7 s.At thi
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Answer:

35 revolutions

Explanation:

t = Time taken

\omega_f = Final angular velocity

\omega_i = Initial angular velocity

\alpha = Angular acceleration

\theta = Number of rotation

Equation of rotational motion

\omega_f=\omega_i+\alpha t\\\Rightarrow \alpha=\frac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha=\frac{3-0}{10.7}\\\Rightarrow \alpha=0.28037\ rev/s^2

\omega_f^2-\omega_i^2=2\alpha \theta\\\Rightarrow \theta=\frac{\omega_f^2-\omega_i^2}{2\alpha}\\\Rightarrow \theta=\frac{3.1^2-0^2}{2\times 0.28037}\\\Rightarrow \theta=17.13806\ rev

Number of revolutions in the 10.7 seconds is 17.13806

\omega_f=\omega_i+\alpha t\\\Rightarrow \alpha=\frac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha=\frac{0-3.1}{11.2}\\\Rightarrow a=-0.27678\ rev/s^2

\omega_f^2-\omega_i^2=2\alpha \theta\\\Rightarrow \theta=\frac{\omega_f^2-\omega_i^2}{2\alpha}\\\Rightarrow \theta=\frac{0^2-3.1^2}{2\times -0.27678}\\\Rightarrow \theta=17.36035\ rev

Number of revolutions in the 11.2 seconds is 17.36035

Total total number of revolutions in the 21.9 second interval is 17.13806+17.36035 = 34.49841 = 35 revolutions

3 0
4 years ago
Why is it important to have a control setup in an experiment?
Lana71 [14]

Explanation:

A control is important for an experiment because it allows the experiment to minimize the changes in all other variables except the one being tested.

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