Answer:
- 6.38x10²² molecules C₆H₁₂O₆
Explanation:
First we <u>convert the given masses into moles</u>, using the <em>compounds' respective molar mass</em>:
- 64.7 g N₂ ÷ 28 g/mol = 2.31 mol N₂
- 83 g CCl₄ ÷ 153.82 g/mol = 0.540 mol CCl₄
- 19 g C₆H₁₂O₆ ÷ 180 g/mol = 0.106 mol C₆H₁₂O₆
Then we multiply each amount by <em>Avogadro's number</em>, to <u>calculate the number of molecules</u>:
- 2.31 mol N₂ * 6.023x10²³ molecules/mol = 1.39x10²⁴ molecules
- 0.540 mol CCl₄ * 6.023x10²³ molecules/mol = 3.25x10²³ molecules
- 0.106 mol C₆H₁₂O₆ * 6.023x10²³ molecules/mol = 6.38x10²² molecules
Answer:
Explanation:
By Ideal Gas Law, P1*V1 / T1 = P2*V2 / T2
So new pressure = (P1*V1 / T1) / (V2 / T2)
= P1*V1*T2 / T1*V2
= 800*3.6*298 / 250*1.8
= 1907.2 mmHg
1 is true,
<span>2 is definitely false </span>
<span>3 is also completely false because </span>
<span>4 is true. </span>
<span>So 1&4 </span>
The pH of a 0.0115 m aqueous formic acid solution is mathematically given as
pH=2.8424
This is further explained below.
<h3>What is the ph of a 0.0115 m aqueous formic acid solution?</h3>
Generally, the equation for the chemical equation is mathematically given as
HCOOH H^+ + HCOO


![&\left[\mathrm{H}^{+}\right]=\mathrm{C \alpha}\\\\&=0.125 \times 0.0115\\\\&=1.4375 \times 10^{-9}\\\\&P=-\log \left[H^{+}\right]\\\\&=-\log \left[1.4375 \times 10^{-3}\right]\\\\&P H=2.8424](https://tex.z-dn.net/?f=%26%5Cleft%5B%5Cmathrm%7BH%7D%5E%7B%2B%7D%5Cright%5D%3D%5Cmathrm%7BC%20%5Calpha%7D%5C%5C%5C%5C%26%3D0.125%20%5Ctimes%200.0115%5C%5C%5C%5C%26%3D1.4375%20%5Ctimes%2010%5E%7B-9%7D%5C%5C%5C%5C%26P%3D-%5Clog%20%5Cleft%5BH%5E%7B%2B%7D%5Cright%5D%5C%5C%5C%5C%26%3D-%5Clog%20%5Cleft%5B1.4375%20%5Ctimes%2010%5E%7B-3%7D%5Cright%5D%5C%5C%5C%5C%26P%20H%3D2.8424)
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The answer is c because bacteria is prokaryote.