All categories

3 years ago

1. What part (or parts) of this system store potential energy?

Physics

1 answer:

choli [55]3 years ago

5 0

Answer:

➢when you crank you make kinetic energy and then the kinetic energy makes potential energy.

Explanation:

hope it will help you have a great day bye and Mark brainlist if the answer is correct

 $kai6417$ 

#carry on learning

You might be interested in

B) A satellite with mass m orbits the Earth at a radius r. A second satellite also with mass m orbits the

Snezhnost [94]

Answer:

So, given the eqn Fg=G(m1+m2/r^2) where G is the gravitational constant, m is the mass of the satellite and m2 is the mass of the earth and r is the distance from earth to the satellite, the force of earths gravity should be quartered.

Cause (2r)^2 gets turned into (4r^2) where 4r^2 is compared to r^2

Explanation:

6 0

3 years ago

8 colors according to their alphabetical order

damaskus [11]

Answer:

8 colors in alphabetical order are

Black

blue

brown

Green

Orange

Pink

Purple

Yellow

Explanation:

6 0

3 years ago

At which position (1,2,3, or 4) does the roller coaster car have the most potential energy? Why?

julsineya [31]

At 1 because the cart is still at the top

3 0

3 years ago

Can the force of gravity cause any deformation to an object?

PSYCHO15rus [73]

Answer:

yes it could deform a shape or an object

Explanation:

5 0

3 years ago

A thin uniform rod of mass M and length L is bent at its center so that the two segments are now perpendicular to each other. Fi

Tatiana [17]

Answer:

(a) I_A=1/12ML²

(b) I_B=1/3ML²

Explanation:

We know that the moment of inertia of a rod of mass M and lenght L about its center is 1/12ML².

(a) If the rod is bent exactly at its center, the distance from every point of the rod to the axis doesn't change. Since the moment of inertia depends on the distance of every mass to this axis, the moment of inertia remains the same. In other words, I_A=1/12ML².

(b) The two ends and the point where the two segments meet form an isorrectangle triangle. So the distance between the ends d can be calculated using the Pythagorean Theorem:

$d=\sqrt{(\frac{1}{2}L) ^{2}+(\frac{1}{2}L) ^{2} } =\sqrt{\frac{1}{2}L^{2} } =\frac{1}{\sqrt{2} } L=\frac{\sqrt{2} }{2} L$

Next, the point where the two segments meet, the midpoint of the line connecting the two ends of the rod, and an end of the rod form another rectangle triangle, so we can calculate the distance between the two axis x using Pythagorean Theorem again:

$x=\sqrt{(\frac{1}{2}L)^{2}-(\frac{\sqrt{2}}{4}L) ^{2} } =\sqrt{\frac{1}{8} L^{2} } =\frac{1}{2\sqrt{2}} L=\frac{\sqrt{2}}{4} L$

Finally, using the Parallel Axis Theorem, we calculate I_B:

$I_B=I_A+Mx^{2} \\\\I_B=\frac{1}{12} ML^{2} +\frac{1}{4} ML^{2} =\frac{1}{3} ML^{2}$

5 0

3 years ago