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4vir4ik [10]
2 years ago
11

At a candy factory, butterscotch candies were

Mathematics
1 answer:
KIM [24]2 years ago
5 0

Answer:

the answer is 2

Step-by-step explanation:

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Whats 2+1*7 nnebfbwjqj
Svetlanka [38]
2+1=3*7=21 hope I helped 
6 0
3 years ago
Read 2 more answers
Urgent please!!! I really don’t understand it, tysm to anyone who can answer thissss :))))
Tomtit [17]

Given:

The frequency distribution table.

To find:

The mean average score on a test.

Solution:

The frequency distribution table is

Marks (x_i)                   Frequency(f_i)                  f_ix_i

     x                                     a                               xa

     y                                     b                               yb

     z                                     c                               zc

  Sum                              a+b+c                          xa+yb+zc

Now, the mean average score on the test is

Mean=\dfrac{\sum f_ix_i}{\sum f_i}

Mean=\dfrac{xa+yb+zc}{a+b+c}

Therefore, the mean average score on the test is \dfrac{xa+yb+zc}{a+b+c}.

3 0
2 years ago
If EH = 76, calculate DI.
Montano1993 [528]

Answer:

DI = 38

Step-by-step explanation:

Δ EHC and Δ DIC are similar and ratios of corresponding sides are equal, that is

\frac{DI}{EH} = \frac{DC}{EC} , substitute values

\frac{DI}{76} = \frac{1}{2}  ( cross- multiply )

2DI = 76 ( divide both sides by 2 )

DI = 38

4 0
2 years ago
Sketch the region enclosed by y=3x and y=x^2 . Then find the area of the region.
kolezko [41]

Answer:

A=4.5u^2

Step-by-step explanation:

The integral of a function gives you the area under the curve, the subtraction of one of the areas from the other will give you the area in between.

The limits of integration are the points where the curves intersect each other(take the curves has a system of equation and solve for x and y):

y=3x, y=x^2\\3x=x^2\\x^2-3x=0\\x(x-3)=0\\x_1=0\\x-3=0\\x_2=3

y_1=3x_1=3(0)=0\\y_2=3x_2=3(3)=9

The integral will be the subtraction of the curve y=3x and y=x^2  (In the graph you can see y=3x is the upper curve):

\int\limits^3_0 {3x-x^2} \, dx =\left\frac{3x^2}{2}-\frac{x^3}{3}\right|^3_0=\frac{3(3)^2}{2}-\frac{(3)^3}{3}-\left(\frac{3(0)^2}{2}-\frac{(0)^3}{3}\right)\\\int\limits^3_0 {3x-x^2} \, dx =\frac{27}{2}-\frac{27}{3} =13.5-9=4.5u^2

6 0
2 years ago
Factor<br> 2) x2 – 3x – 18
Anna71 [15]

Answer:

By inspection you need 2 numbers that multiply together to 18 and sum to 3. These numbers are 6 and 3. Therefore we have to find the value of x but we dont have that so we have this:

x to the power of 2-3x - 18 = ( X - 6) ( x + 3)

6 0
3 years ago
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