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4vir4ik [10]
2 years ago
11

At a candy factory, butterscotch candies were

Mathematics
1 answer:
KIM [24]2 years ago
5 0

Answer:

the answer is 2

Step-by-step explanation:

You might be interested in
Which expression is equivalent to (5.4x10^10) (3.3x10^21)?
natta225 [31]

Although, here are no expressions ! it's an incomplete question. So, showing the answer with general simplification 17.82(10^{31}).

<u>Step-by-step explanation:</u>

We have the expression as (5.4x10^10) (3.3x10^21) which can be further simplified as :

⇒(5.4x10^10) (3.3x10^21)

⇒(5.4(10^{10})(3.3(10^{21})

keep the power terms together and numbers to simply. Hence, we get as below

⇒ (5.4(3.3))(10^{21}.10^{10})

⇒(17.82)(10^{21+10)})

By solving the above, we get final simplified answer as

⇒17.82(10^{31})

Although, here are no expressions ! it's an incomplete question . You may match  17.82(10^{31}) to the listed options wherever!

4 0
3 years ago
Please someone help I don’t understand this
irina [24]

Answer:

336

Step-by-step explanation:

5 0
3 years ago
What adds to get 3 but multiplies to get negative 18
Colt1911 [192]
6 and -3

6 + -3 = 3

6  x -3 = -18

Hope that helps! 
3 0
3 years ago
Is 2/4 greater than or less than 1/2?
Paladinen [302]

Answer:

2/4 is equal to 1/2

Step-by-step explanation:

1/2 is equal to 2/4 because 1/2 x 2 for each the numerator and the denominator.

7 0
3 years ago
Read 2 more answers
In how many ways can a quality-control engineer select a sample of3 transistors for testing frm a batch of 100 transistors?
Advocard [28]

Answer:

161700 ways.

Step-by-step explanation:

The order in which the transistors are chosen is not important. This means that we use the combinations formula to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

3 transistors from a set of 100. So

C_{100,3} = \frac{100!}{3!(100-3)!} = 161700

So 161700 ways.

6 0
3 years ago
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