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Travka [436]
3 years ago
5

57 students choose to attend one of three after school activities: football, tennis or running.

Mathematics
1 answer:
skelet666 [1.2K]3 years ago
3 0

The probability that the randomly selected student chose running is; 12/57

<h3>Solving Probability Questions</h3>

Total number of students = 57

Total number of boys = 24

Total number of girls = 33

Number of Girls that chose football = 17

Number of boys that chose football = 14

Number of students that chose Tennis = 14

Now, number of students that chose running will be;

Number of students that chose running = 57 - (31 + 14) = 12

Thus, probability that a randomly selected student chose running = 12/57

Read more about probability selection at; brainly.com/question/251701

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A rancher needs to enclose two adjacent rectangular​ corrals, one for cattle and one for sheep. If the river forms one side of t
Serga [27]
Basically, what this asks you is to maximize the are A=ab where a and b are the sides of the recatangular area (b is the long side opposite to the river, a is the short side that also is the common fence of both corrals). Your maximization is constrained by the length of the fence, so you have to maximize subject to 3a+b=450 (drawing a sketch helps - again, b is the longer side opposite to the river, a are the three smaller parts restricting the corrals)
3a+b = 450
b = 450 - 3a
so the maximization max(ab) becomes
max(a(450-3a)=max(450a-3a^2)
Since this is in one variable, we can just take the derivative and set it equal to zero:
450-6a=0
6a=450
a=75
Plugging back into b=450-3a yields
b=450-3*75
b=450-225
b=215
Hope that helps!
5 0
3 years ago
Carisoprodol, a generic muscle relaxer, claims to have, on average, at least 120 milligrams of active ingredient. An independent
katovenus [111]

Answer:

The approximate p-value for the suitable test

<em>0.05 < p < 0.1</em>

|t| = |-1.5806| = 1.5806

t = 1.5806 < 2.009 at 0.05 level of significance

<em>Carisoprodol, a generic muscle relaxer, claims to have, on average, is equal to 120 milligrams of active ingredient.</em>

<u>Step-by-step explanation</u>:

<u><em>Step(i)</em></u>:-

Given mean of the Population 'μ' = 120 milligrams

Given random sample size  'n' = 50

Given mean of the sample x⁻ = 116.2 milligrams

Standard deviation of the sample 'S' = 17 milligrams

Null hypothesis :  'μ' = 120

Alternative hypothesis : 'μ' < 120

<u><em>Step(ii):</em></u>-

<em>Test statistic </em>

t = \frac{x^{-} -mean}{\frac{S}{\sqrt{n} } }

t = \frac{116.2 - 120}{\frac{17}{\sqrt{50} } } = \frac{-3.8}{2.404} = -1.5806

<em>Degrees of freedom</em>

<em>ν = n-1 = 50 -1 =49</em>

t₀.₀₅ = 2.009

|t| = |-1.5806| = 1.5806

t = 1.5806 < 2.009 at 0.05 level of significance

<em>Null hypothesis is accepted</em>

<em>Carisoprodol, a generic muscle relaxer, claims to have, on average, is equal to 120 milligrams of active ingredient.</em>

<u><em>P- value:-</em></u>

<em>The test statistic |t| = 1.5806 at 49 degrees of freedom</em>

<em>The test statistic value is lies between 0.05 to 0.1</em>

<em>0.05 < p < 0.1</em>

<u><em></em></u>

3 0
3 years ago
James and sarah went out to lunch the price of lunch for both of them was $20 they tip their server 20% of that amount how much
sleet_krkn [62]
20% of $20 is $4
So add that amount to the price of the meal and you have $24
Since they split the total cost evenly, the price for each is 24 ÷ 2
= <u>$12</u>
6 0
3 years ago
Which is the most accurate estimate of 27% of 39 ?
DochEvi [55]

Answer:

The would be 69.23%

Step-by-step explanation:

27:39*100 =

(27*100):39 =

2700:39 = 69.23

hope that helps

3 0
3 years ago
Read 2 more answers
= The average score of Karl's first four math tests is 72 points. After the fifth and the sixth tests, his average score increas
mylen [45]

Answer:

83 points

Step-by-step explanation:

-The formula for average is given as:

\bar X=\frac{1}{n}\sum{x_i}\\\\x_i=Individual \ Test \ scores\\n=number \ of \ scores

Let a be his 5th score and (a+4) of the 6th

#We subtract the sum of the first 4 tests from the 6, to get the sum of the 5th and 6th tests:

(6^{th}+5^{th})=\bar X n_6-\bar X n_4\\\\=75\times 6-72\times 4\\\\=162

#We substitute for the 5th and 6th to solve a:

5^{th}=a\\6^{th}=a+4\\\\a+(a+4)=162\\\\2a=158\\\\a=79\\\\6^{th}=a+4=79+4=83

Hence, Karl score 83 points in his 6th test.

5 0
3 years ago
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