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MrRissso [65]
2 years ago
15

The following equation represents which of the following types of reaction?

Chemistry
1 answer:
nataly862011 [7]2 years ago
3 0

Answer:

A. decomposition.

Explanation:

Recall the types of chemical reactions and how they are typically written.

Synthesis : A + B ==> AB

Decomposition : AB ==> A + B

Double Replacement : AB + CD ==> AC + BD

Single Replacement : AB + C ==> AC + B

Now although it may seem that the given equation doesnt follow any of these as it has more parts, it follows decomposition.
Decomposition is simply a single compound being broken up into two or more products. So it can be written as ABC ==> A + B + C as well therefore the answer is A

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You determine that it takes 26.0 mL of base to neutralize a sample of your unknown acid solution. The pH of the solution when ex
mojhsa [17]

Answer:

a. 1.78x10⁻³ = Ka

2.75 = pKa

b. It is irrelevant.

Explanation:

a. The neutralization of a weak acid, HA, with a base can help to find Ka of the acid.

Equilibrium is:

HA ⇄ H⁺ + A⁻

And Ka is defined as:

Ka = [H⁺] [A⁻] / [HA]

The HA reacts with the base, XOH, thus:

HA + XOH → H₂O + A⁻ + X⁺

As you require 26.0mL of the base to consume all HA, if you add 13mL, the moles of HA will be the half of the initial moles and, the other half, will be A⁻

That means:

[HA] = [A⁻]

It is possible to obtain pKa from H-H equation (Equation used to find pH of a buffer), thus:

pH = pKa + log₁₀ [A⁻] / [HA]

Replacing:

2.75 = pKa + log₁₀ [A⁻] / [HA]

As [HA] = [A⁻]

2.75 = pKa + log₁₀ 1

<h3>2.75 = pKa</h3>

Knowing pKa = -log Ka

2.75 = -log Ka

10^-2.75 = Ka

<h3>1.78x10⁻³ = Ka</h3>

b. As you can see, the initial concentration of the acid was not necessary. The only thing you must know is that in the half of the titration, [HA] = [A⁻]. Thus, the initial concentration of the acid doesn't affect the initial calculation.

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Why is there no set path that a scientific inquiry must follow
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