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UkoKoshka [18]
3 years ago
12

Why is an energy source needed in order to have a working electric circuit

Chemistry
1 answer:
alex41 [277]3 years ago
6 0
That's easy. Because then you won't have energy
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What type of reaction is illustrated?
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Ngl Im not sure

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______ break down sugars to produce energy.
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mitochondria

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Wich substances is most likely to form in a precipitation reaction?
Flura [38]

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A precipitation reaction refers to the formation of an insoluble salt when two solutions containing soluble salts are combined. The insoluble salt that falls out of solution is known as the precipitate, hence the reaction's name.

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3 years ago
Listed following are some distinguishing characteristics of comets, meteors, and asteroids. Match these to the appropriate categ
9966 [12]

The distinguishing characteristics of comets, meteors, and asteroids are its composition.

<h3>What are the characteristics of comets, meteors and asteroids?</h3>

Asteroids are the fragments of rock that were left over from the creation of the solar system, Meteors are the rocks that enter the atmosphere of the Earth from space while on the other hand, Comets are the remnants of the formation of the solar system that are made of dust, rocks, and ice. All these materials i.e. comets, meteors and asteroids are different from one another due to its structure and chemical composition.

So we can conclude that the distinguishing characteristics of comets, meteors, and asteroids are its composition.

Learn more about asteroids here: brainly.com/question/11996385

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5 0
2 years ago
Calculate the percentage of each element in acetic acid, hc2h3o2, and glucose, c6h12o6.
My name is Ann [436]
<em>Acetic acid, HC2H3O2</em>

First, calculate for the molar mass of acetic acid as shown below.
    M = 1 + 2(12) + 3(1) + 2(16) = 60 g

Then, calculating for the percentages of each element.
<em> Hydrogen:</em>
    P1 = ((4)(1)/60)(100%) = <em>6.67%</em>

<em> Carbon:</em>
   P2 = ((2)(12)/60)(100%) = <em>40%</em>

<em>Oxygen</em>
  P3 =((2)(16) / 60)(100%) = <em>53.33%</em>

<em>Glucose, C6H12O6</em>

The molar mass of glucose is as calculated below,
   6(12) + 12(1) + 6(16) = 180

The percentages of the elements are as follow,
 <em> Hydrogen:</em>
   P1 = (12/180)(100%) = <em>6.67%</em>

<em>Carbon:</em>
  P2 = ((6)(12) / 180)(100%) = <em>40%</em>

<em>Oxygen:</em>
  P3 = ((6)(16) / 180)(100%) = <em>53.33%</em>

b. Since the empirical formula of the given substances are just the same and can be written as CH2O then, the percentages of each element composing them will just be equal. 
6 0
3 years ago
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