Answer:
The new moles of the gas in the flask is 2.13 moles.
Explanation:
Given;
number of moles of gas, n = 1.9 mol
temperature of the gas, T = 21 °C = 21 + 273 = 294 K
pressure of gas, P = 697 mmHg
volume of gas, V = ?
Apply ideal gas law;
PV = nRT
Where;
R is gas constant, = 62.363 mmHg.L / mol. K
V = nRT / P
V = (1.9 x 62.363 x 294) / 697
V = 49.98 L
New pressure of the gas, P = 795 mmHg
New temperature of the gas, T = 26 °C = 273 + 26 = 299 K
New moles of the gas, n = ?
Volume of the gas is constant because volume of the flask is the same when more gas was added.
n = PV / RT
n = (795 x 49.98) / (62.363 x 299)
n = 2.13 moles
Therefore, the new moles of the gas in the flask is 2.13 moles.
