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4 years ago

What is the formula for dihydrogen tetraoxide

Chemistry

1 answer:

Veseljchak [2.6K]4 years ago

3 0

It's been a while... but I'm pretty sure it's

H₂O₄

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Determine the formula of chromic acid.

Katyanochek1 [597]

Answer: The formula of chromic acid is $H_2CrO_4$

Explanation:

We are given an ionic compound named as chromic acid. This acid is formed by the combination of hydrogen ion and chromate ion.

An acid is defined as the substance which releases hydrogen ion when dissolved in water.

Hydrogen is the 1st element of periodic table having electronic configuration of $1s^1$ .

This element will loose 1 electron to form $H^{+}$ ion.

Chromate ion is a polyatomic ion having chemical formula of $CrO_4^{2-}$

By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.

So, the chemical formula for the given compound is $H_2CrO_4$

Thus, the formula of chromic acid is $H_2CrO_4$

8 0

3 years ago

Olivia, a Latina student, is told that she can check only two books out of the library at a time, but Leann, a white student, is

Sliva [168]

Answer:

Explanation:

the others are rude, and rather support this, while a helps to support the ending of white privlige

4 0

3 years ago

Read 2 more answers

What independent variables can be tested in this lab setup? (List at least 5)

tigry1 [53]

Answer:

I know 2

dependent

independent

Explanation:

sorry that's about it from me

6 0

3 years ago

A sample of an unknown substance has a mass of 42g and a volume of

hjlf

Answer: 1.5 g/cm^3

Explanation:

Density is mass over volume

42g / 28 cm^3 = 1.5 g/cubic cm

hope this helps

5 0

3 years ago

Read 2 more answers

Help it’s about Binary compounds and transition metals

Musya8 [376]

Answer:

Cr 6+ & SO4 2-

Explanation:

Sulfate is a polyatomic ion that has a charge of 2-. There are three of them in the chemical formula so it equates to a 6- total charge. Thus, chromium must have a 6+ charge to give the compound a neutral charge.

8 0

3 years ago