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Igoryamba
3 years ago
9

What is the formula for dihydrogen tetraoxide

Chemistry
1 answer:
Veseljchak [2.6K]3 years ago
3 0

It's been a while... but I'm <em>pretty</em> sure it's

H₂O₄

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Which is NOT a type of fracture?
Andrews [41]
B. Perfect ---------
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How many grarns would 3 moles of carbon dioxide (CO2) weigh? (round to the
BigorU [14]

Mass of CO₂ = 132 g

<h3>Further explanation   </h3>

A mole is a number of particles(atoms, molecules, ions)  in a substance

This refers to the atomic total of the 12 gr C-12  which is equal to 6.02.10²³, so 1 mole = 6.02.10²³ particles  

Can be formulated :

N = n x No

N = number of particles

n = mol

No = 6.02.10²³ = Avogadro's number

mole also can be formulated :

\tt n=\dfrac{mass}{MW}

moles of CO₂ = 3

mass of CO₂(MW=44.01 g/mol) :

\tt mass=mol\times MW\\\\mass=3\times 44.01\\\\mass=132.03~g\approx 132~g

6 0
3 years ago
Which describes the difference between frogs and bacteria?
likoan [24]

Answer:the first one

Explanation:Bacteria living on the skin of frogs could save them from a deadly virus, ... With Differences in the Composition of the Skin Microbiome of a Wild

6 0
3 years ago
Read 2 more answers
In a certain time, light travels 4.96 km in a vacuum. during the same time, light travels only 3.36 km in a liquid. what is the
Natali5045456 [20]

the refractive index of the liquid is 1.476

The refractive index, which has no dimensions, measures how quickly light passes through a substance.

It can also be described as the difference between the speed of light in a vacuum and a medium.

Refractive index is equal to the product of the light's liquid and vacuum speeds.

Therefore.

speed of light in vacuum = 4.96 km/t

speed of light in liquid = 3.36 km/t

Refractive index = 4.96/3.36

Refractive index =1.476

Therefore, the refractive index of the liquid is 1.476

To learn more about refractive index

brainly.com/question/23750645

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6 0
1 year ago
A rigid tank that contains 2 kg of N2 at 25°C and 550 kPa is connected to another rigid tank that contains 4 kg of O2 at 25°C an
koban [17]

Answer:

The volume in the first tank = 0.32 m^{3}

The volume in the second tank = 2.066 m^{3}

The  final pressure of the mixture = 203.64 K pa

Explanation:

<u>First Tank </u>

Mass = 2 kg

Pressure = 550 k pa

Temperature = 25 °c = 298 K

Gas constant for nitrogen = 0.297 \frac{KJ}{Kg K}

From the ideal gas equation

P V = m R T

550 × V = 2 × 0.297 × 298

V = 0.32 m^{3}

This is the volume in the first tank.

<u>Second tank</u>

Mass =  4 kg

Pressure = 150 K pa

Temperature = 25 °c = 298 K

Gas constant for oxygen = 0.26  \frac{KJ}{Kg K}

From the ideal gas equation

P V = m R T

150 × V = 4 × 0.26 × 298

V = 2.066 m^{3}

This is the volume in the second tank.

This is the iso thermal mixing. i.e.

P_{3} V_{3}  = P_{1} V_{1} + P_{2} V_{2} ----- (1)

V_{3}  = V_{1}  + V_{2}

V_{3}  = 0.32 + 2.066

V_{3}  = 2.386 \ m^{3}

Put this value in equation (1)

P_{3} × 2.386 =  550 × 0.32 + 150 × 2.066

P_{3} = 203.64 K pa

Therefore the  final pressure of the mixture = 203.64 K pa

3 0
3 years ago
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