All categories

2 years ago

1CuCl2 + 2Na(NO3) --> 1Cu(NO3)2 + 2NaCl

Chemistry

1 answer:

vivado [14]2 years ago

3 0

Answer:

13.45 grams of NaCl will be produced

Explanation:

Given:

Mass of CuCl2 = 15 grams

Molar mass of CuCl2 = 134.5 g/mol

Mass of Na(NO3) = 20grams

Molar mass of Na(NO3) = 85 g/mol

To find:

Amount of Sodium chloride produced = ?

Solution:

No of moles of CuCl2 = 15/134.5 = 0.11 moles

No of moles of Na(NO3) = 20/85 = 0.23 moles,

1CuCl2 + 2Na(NO3) --> 1Cu(NO3)2 + 2NaCl

from the reaction, 1 mole of copper chloride reacts with 2 mole of NaNO3 to produce 2 moles of sodium chloride.

Hence, 0.11 mole of copper chloride will react with 0.23 mole of NaNO3 to produce 0.23 moles of sodium chloride.

Mass of 0.23 moles of NaCl = 0.23 × M.M of NaCl

(Molar mass of NaCl = 58.5)

Mass of 0.23 moles of NaCl = 0.23 × 58.5 = 13.45 grams

Thanks for joining brainly community.

You might be interested in

What happens in this reaction and why? hept-3-yne + Br2 -->

maw [93]

Here we have to explain and predict the product of the reaction between hept-3-yne and bromine (Br₂)

The reaction between hept-3-yne and bromine produces trans-3,4-dibromo-3-heptene.

The reaction between the unsaturated hydrocarbon with halogen remove the unsaturation in the molecule and produces di halo compound. The reaction proceed through the formation of bromonium ion.

In this reaction as the unsaturation present in the middle of the alkyl chain i.e. hept-3-yne. The reaction will stop after the formation of di-halo compound with one double bond as shown in the figure.

The product will be exclusively trans product as the bromine is a bulky group and the formation of bromonium ion (intermediate) will be one side of the unsaturated compound.

6 0

3 years ago

The water bottle contains 575 grams of water at 80°C. The water eventually cools to

Jet001 [13]

Answer:

–23000 Calories.

NOTE : The negative sign indicates that heat has been loss to the student back.

Explanation:

The following data were obtained from the question:

Mass (M) of water = 575 g

Initial temperature (T1) = 80 °C

Final temperature (T2) = 40 °C

Heat (Q) transferred =.?

Next, we shall determine the change in temperature (ΔT).

This is illustrated below:

Initial temperature (T1) = 80 °C

Final temperature (T2) = 40 °C

Change in temperature (ΔT) =?

Change in temperature (ΔT) = T2 – T1

Change in temperature (ΔT) = 40 – 80

Change in temperature (ΔT) = –40°C

Finally, we shall determine the heat transferred. This can be obtained as follow:

Mass (M) of water = 575 g

Change in temperature (ΔT) = –40°C

Specific heat capacity (C) of water = 1 Cal/g°C

Heat (Q) transferred =.?

Q = MCΔT

Q = 575 × 1 × –40

Q = –23000 Calories

NOTE : The negative sign indicates that heat has been loss to the student back.

8 0

3 years ago

URGENT

Mumz [18]

The celery and carrot will most likely become saltier and perhaps more shriveled because of the high concentration of salt in the water solution compared to the low concentration of salt in the solution. The raisin, however, could take two roots, one would be the same as the carrot and celery, but the other one is it would soak up water because of how salty and shriveled the raisin already is.

7 0

3 years ago

Read 2 more answers

The density of silver is 10.49 g/mL. If a sample of pure silver has a volume of 12.993 mL, what is the mass of the silver?

r-ruslan [8.4K]

Answer:

see the pic for more detail