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Reika [66]
3 years ago
15

While the reaction in the lab text gives the product 4-methylcyclohexene, it is possible that several products are formed in thi

s reaction, including 1-methylcyclohexene, because of 1,2-hydride shifts in the carbo-cation intermediate. Show a step-wise, arrow-pushing mechanism for the formation of 1-methylcyclohexene.

Chemistry
1 answer:
Contact [7]3 years ago
6 0

Answer:

Explanation:

The step wise reaction mechanism for the formation of 1-methylcyclohexene is as follows.

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What is the meaning of the term polar as applied to chemical bonding?
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2 years ago
What is the mass of an atom that has 9 protons, 11 neutrons, and 10 electrons
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Answer: By looking at the periodic table, you will see that Fluorine has 9 protons. Since the number of electrons equal the number of protons, Fluorine has 9 electrons as well. Meanwhile, it's mass number of 19, minus 10 neutrons, gives you 9 protons or electrons. Hence, the atom would be Fluorine.

Explanation:

6 0
2 years ago
Read 2 more answers
The decomposition of hydrogen peroxide follows first order kinetics and has a rate constant of 2.54 x 10-4 s-1 at a certain temp
pav-90 [236]

<u>Answer:</u> The initial concentration of hydrogen peroxide at the given temperature is 0.399 M

<u>Explanation:</u>

Decomposition of hydrogen peroxide is following first order kinetics.

Rate law expression for first order kinetics is given by the equation:

k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}

where,  

k = rate constant = 2.54\times 10^{-4}s^{-1}

t = time taken for decay process = 855 s

[A_o] = initial amount of the reactant = ?

[A] = amount left after decay process =  0.321 M

Putting values in above equation, we get:

2.54\times 10^{-4}s^{-1}=\frac{2.303}{855s}\log \frac{[A_o]}{0.321}

[A_o]=0.399M

Hence, the initial concentration of hydrogen peroxide at the given temperature is 0.399 M

7 0
3 years ago
Lead(II) nitrate and ammonium iodide react to form lead(II) iodide and ammonium nitrate according to the reaction Pb ( NO 3 ) 2
nikklg [1K]

Answer : The volume of NH_4I solution required is, 2.93 L

The number of moles of PbI_2 formed from the reaction is, 0.662 moles.

Explanation :

First we have to calculate the initial moles of Pb(NO_3)_2.

\text{Moles of }Pb(NO_3)_2=\text{Concentration of }Pb(NO_3)_2\times \text{Volume of solution}

\text{Moles of }Pb(NO_3)_2=0.700M\times 0.945L=0.662mol

Now we have to calculate the moles of NH_4I

The balanced chemical reaction is:

Pb(NO_3)_2(aq)+2NH_4I(aq)\rightarrow PbI_2(s)+2NH_4NO_3(aq)

From the balanced chemical reaction we conclude that,

As, 1 mole of Pb(NO_3)_2 react with 2 moles of NH_4I

So, 0.662 mole of Pb(NO_3)_2 react with 0.662\times 2=1.32 moles of NH_4I

Now we have to calculate the volume of NH_4I

\text{Volume of }NH_4I=\frac{\text{Moles of }NH_4I}{\text{Concentration of }NH_4I}

\text{Volume of }NH_4I=\frac{1.32mol}{0.450mol/L}=2.93L

Now we have to calculate the moles of PbI_2

From the balanced chemical reaction we conclude that,

As, 1 mole of Pb(NO_3)_2 react to give 1 moles of PbI_2

So, 0.662 mole of Pb(NO_3)_2 react to give 0.662 moles of PbI_2

Thus, the number of moles of PbI_2 formed from the reaction is, 0.662 moles.

7 0
3 years ago
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