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Reika [66]
3 years ago
15

While the reaction in the lab text gives the product 4-methylcyclohexene, it is possible that several products are formed in thi

s reaction, including 1-methylcyclohexene, because of 1,2-hydride shifts in the carbo-cation intermediate. Show a step-wise, arrow-pushing mechanism for the formation of 1-methylcyclohexene.

Chemistry
1 answer:
Contact [7]3 years ago
6 0

Answer:

Explanation:

The step wise reaction mechanism for the formation of 1-methylcyclohexene is as follows.

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In an acid-base titration,
Lemur [1.5K]

Answer:

b

Explanation:

An acid-base titration is an experimental procedure used to determined the unknown concentration of an acid or base by precisely neutralizing it with an acid or base of known concentration. ... It is filled with a solution of strong acid (or base) of known concentration.

7 0
3 years ago
Question 2
Thepotemich [5.8K]

Answer:

1-Pentene

Explanation:

If we look at all the options listed, we will notice that the rate of reaction of bromine with each one differs significantly.

For 1-pentene, addition of bromine across the double bond is a relatively fast process. It is usually used as a test for unsaturation. Bromine water is easily decolorized by alkenes.

Cyclohexane, heptane are alkanes. They can only react with chlorine in the presence of sunlight. This is a substitution reaction. It does not occur easily. A certain quantum of light is required for the reaction to occur.

For benzene, bromine can only react with it by electrophilic substitution in which the benzene ring is retained. A Lewis acid is often required for the reaction to occur and it doesn't occur easily.

3 0
3 years ago
The standard reduction potentials of lithium metal and chlorine gas are as follows:Reaction Reduction potential(V)Li+(aq)+e−→Li(
meriva

Answer:

A) E° = 4.40 V

B) ΔG° = -8.49 × 10⁵ J

Explanation:

Let's consider the following redox reaction.

2 Li(s) +Cl₂(g) → 2 Li⁺(aq) + 2 Cl⁻(aq)

We can write the corresponding half-reactions.

Cathode (reduction): Cl₂(g) + 2 e⁻ → 2 Cl⁻(aq)      E°red = 1.36 V

Anode (oxidation):  2 Li(s) → 2 Li⁺(aq) + 2 e⁻         E°red = -3.04

<em>A) Calculate the cell potential of this reaction under standard reaction conditions.</em>

The standard cell potential (E°) is the difference between the reduction potential of the cathode and the reduction potential of the anode.

E° = E°red, cat - E°red, an = 1.36 V - (-3.04 V) 4.40 V

<em>B) Calculate the free energy ΔG° of the reaction.</em>

We can calculate Gibbs free energy (ΔG°) using the following expression.

ΔG° = -n.F.E°

where,

n are the moles of electrons transferred

F is Faraday's constant

ΔG° = - 2 mol × (96468 J/V.mol) × 4.40 V = -8.49 × 10⁵ J

8 0
3 years ago
The Groups 1 and 2 on the periodic table contain what atom type?
Bumek [7]
Non metals
and metals
8 0
3 years ago
Read 2 more answers
In converting between units, it is never necessary to use more than one conversion factor. A. True B. False
lakkis [162]
False, in converting between units, it is never necessary to use more than one conversion factor.
6 0
3 years ago
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