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3 years ago

What is this math i do not get it pls helppppp

Physics

2 answers:

babunello [35]3 years ago

6 0

Answer:

where is the problem u need help with

Explanation:

(: pls mark brainliest

Marizza181 [45]3 years ago

4 0

Answer: math is an area of knowledge that includes the study of such topics. as numbers and formulas related structures, algebra and geometry also calculus and analysis

Explanation:

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Everybody can you post the lyrics to your favorite song? I'll give brainliest if I know the song or if I like the lyrics, I'll b

andrezito [222]

Answer:

Show and tell

I'm on display for all you (bad word) to see

Show and tell

Harsh words if you don't get a pic with me

Buy and sell (buy and sell me, baby)

Like I'm a product to society

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Unless you (bad word) every authority

Explanation:

4 0

3 years ago

Read 2 more answers

A shot-putter exerts an unbalanced force of 128 N on a shot giving it an acceleration of 19

IRISSAK [1]

Answer:

128 is the ans cuz N is also lnown as mass

Explanation:

128

6 0

3 years ago

At a distance of 41 ft , an ionizing radiation source delivers 5.0 rem of radiation. How close could you get to the source and s

mash [69]

Answer:

at distance 18.33 ft no biological effects

Explanation:

given data

distance = 41 ft

radiation = 5 rem

to find out

how close get so no biological effects

solution

we know here that intensity of radiation R is inversely proportional to (radiation)²

so here equation will be

$\frac{I1}{I2} = (\frac{R2}{R1})^{2}$ .............1

here I is intensity

so here I1 = 25

because for 0 to 25 there is no detectable effects and for 25 to 100 it will . temporary decrease so

we take 25 because dose is less than 25 so we take that highest value

$\frac{I1}{I2} = (\frac{R2}{R1})^{2}$

$\frac{25}{5} = (\frac{41}{R1})^{2}$

R1 = 18.33 ft

so at distance 18.33 ft no biological effects

6 0

3 years ago

How long does it take for earth to complete one full rotation?

Gwar [14]

Answer:

23 hours 56 minutes 4.091 seconds

Explanation:

3 0

2 years ago

A uniform 1.4-kg rod that is 0.75 m long is suspended at rest from the ceiling by two springs, one at each end of the rod. Both

svetlana [45]

Answer:

7 deg

Explanation:

$m$ = mass of the rod = $1.4 kg$

$W$ = weight of the rod = $mg = (1.4) (9.8) = 13.72 N$

$k_{L}$ = spring constant for left spring = $59 Nm^{-1}$

$k_{R}$ = spring constant for right spring = $33 Nm^{-1}$

$x_{L}$ = stretch in the left spring

$x_{R}$ = stretch in the right spring

$L$ = length of the rod = 0.75 m

$\theta$ = Angle the rod makes with the horizontal

Using equilibrium of force in vertical direction for left spring

$k_{L} x_{L} = (0.5) W\\(59) x_{L} = (0.5) (13.72)\\x_{L} = 0.116 m$

Using equilibrium of force in vertical direction for right spring

$k_{R} x_{R} = (0.5) W\\(33) x_{R} = (0.5) (13.72)\\x_{R} = 0.208 m$

Angle made with the horizontal is given as

$\theta = tan^{-1}(\frac{(x_{R} - x_{L})}{L} )\\\theta = tan^{-1}(\frac{(0.208 - 0.116)}{0.75} )\\\theta = 7 deg$

3 0

3 years ago