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madreJ [45]
2 years ago
5

A basketball player makes a jump shot. The 0.630-kg ball is released at a height of 1.80 m above the floor with a speed of 7.09

m/s. The ball goes through the net 3.03 m above the floor at a speed of 4.21 m/s. What is the work done on the ball by air resistance, a nonconservative force
Physics
1 answer:
N76 [4]2 years ago
6 0

mass of the ball m = 0.63 kg

initial height h = 1.8 m

final height h ' = 3.03 m

initial speed v = 7.09 m / s

final speed v ' = 4.21 m / s

Let the work done on the ball by air resistance W = ?

we know from law of conservation of energy ,

total energy at height h + work done by air = total energy at height h '

  mgh + ( 1/ 2) mv^ 2 + W = mgh ' + ( 1/ 2) mv'^ 2

0.630*9.8*1.8 + 0.63*7.09^2 + W = mgh ' + ( 1/ 2) mv'^ 2

From there you can find W

if there is negative sign indicates it work opposite direction to motion

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Answer:

The energy of an electron in the 8th shell is given by:  -0.2125 eV

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The number of orbitals is:  64

The number of electrons that fit on this shell is: 128

Explanation:

First, we find the energy of the electrons in the 8th shell. In order to do this, we recall that the energy of an electron (in the Hydrogen atom) whose principal number is n is given by:

E_{n}=-13.6\frac{1}{n^{2}}

Substituting n=8, we find that the energy is given by:

E_{8} = -13.6\frac{1}{8^{2}}=-0.2125

In order to find the number of subshells we recall that, for a given principal quantum number n, the possible values of the quantum number l, which corresponds to the number of subshells are:

0, 1, 2, ... , n-1

Since n = 8 in our problem, the possible values of l are: 0, 1, 2, 3, 4, 5, 6, 7. Therefore, the number of subshells are 8.

Now we continue with the number of orbitals. For every subshell l, we have 2l+1 possible values of m, which correspond to the orbitals. Since the possible values of l are: 0,1,2,3,4,5,6,7, therefore, we have to perform the sum:

\sum_{l=0}^{7}(2l+1) = 8^2=64

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