Answer:
a) 0.64 b) 2.17m/s^2 c) 8.668joules
Explanation:
The block was on the ramp, the ramp was inclined at 20degree. A force of 5N was acting horizontal to the but not parallel to the ramp,
Frictional force = horizontal component of the weight of the block along the ramp + the applied force since the block was just about move
Frictional force = mgsin20o + 5N = 6.71+5N = 11.71
The force of normal = the vertical component of the weight of the block =mgcos20o = 18.44
Coefficient of static friction = 11.71/18.44= 0.64
Remember that g = acceleration due to gravity (9.81m/s^2) and m = mass (2kg)
b) coefficient of kinetic friction = frictional force/ normal force
Fr = 0.4* mgcos 20o = 7.375N
F due to motion = ma = total force - frictional force
Ma = 11.71 - 7.375 = 4.335
a= 4.335/2(mass of the block) = 2.17m/s^2
C) work done = net force *distance = 4.335*2= 8.67Joules
The length of copper wire this motorcyclist must use is equal to 8.56 meters.
<u>Given the following data:</u>
- Voltage of the motorcycle, V = 12 V
- Diameter of the copper wire, d = 0.25 mm
- Current in the wire, I = 4.0 A
Radius, r = diameter/2 = 0.12.5 mm = 0.000125 m.
Resistivity of the copper wire, ρ = 1.72 × 10⁻⁸ Ω-m.
<h3>How to determine the
resistance?</h3>
By applying Ohm's law, the resistance of this copper wire can be calculated by using this formula:
R = V/I
R = 12/4
Resistance, R = 3 Ohms.
Mathematically, the resistance of any conductor (wire) in terms of length is given by this formula:
Length = RA/ρ
Length = Rπr²/ρ
Length = [3 × 3.142 × (0.000125)²]/1.72 × 10⁻⁸
Length = 14.73 × 10⁻⁷/1.72 × 10⁻⁸
Length = 8.56 meters.
Read more on resistance and length here: brainly.com/question/13930397
#SPJ4
Answer:
This is due to the gap in between the switch. So the applied energy is not converted to current even though the resistance is still there. Hence voltage will be there, where you applied it
Explanation:
2. $39
3. 1 - $100 4 - $10 and 2 - $1