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Nonamiya [84]
3 years ago
6

Một đĩa tròn có bán kính 20cm đang đứng yên, được quanh nhanh dần đều sau 10s thì đạt vận tốc góc 180 vòng/phút. Hãy xác định: a

. Gia tốc góc của đĩa và số vòng đĩa quay được. b. Khi đang quay với 180 vòng/phút thì đĩa bị hãm phanh với lực không đổi sau 10s thì còn 90 vòng/phút. Tính gia tốc góc, số vòng và thời gian đĩa quay được kể từ lúc hãm phanh.
Physics
1 answer:
masya89 [10]3 years ago
7 0

this made my day happyf77d3

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At high speeds, a particular automobile is capable of an acceleration of about 0.540 m/s^2. At this rate, how long (in seconds)
Mama L [17]

Answer:

t = 6.68 seconds

Explanation:

The acceleration of the automobile, a=0.54\ m/s^2

Initial speed of the automobile, u = 91 km/hr = 25.27 m/s

Final speed of the automobile, v = 104 km/hr = 28.88 m/s

Let t is the time taken to accelerate from u to v. It can be calculated as the following formula as :

t=\dfrac{v-u}{a}

t=\dfrac{28.88-25.27}{0.54}

t = 6.68 seconds

So, the time taken by the automobile to accelerate from u to v is 6.68 seconds. Hence, this is the required solution.

5 0
3 years ago
Two car horns are sounded creating two sound waves with frequencies that differ by a factor of three. How does the speed of the
Andrews [41]

Answer:

Remains the same

Explanation:

The speed of waves of higher and lower frequency both will be same.

the speed of sound in a medium is constant  and independent of it's frequency. Moreover, when the frequency changes wavelength changes accordingly, such that their product remains constant.

we know that

υ×λ = constant = velocity

υ= frequency

λ= wavelength.

7 0
3 years ago
The amount of work done against friction to slide a box in a straight line across a uniform, horizontal floor depends most on th
Ivenika [448]
Amount of force that is applied to the box
7 0
3 years ago
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A 2kg water balloon is flying at a rate of 4m/s^2. With what force will it hit its target?
blondinia [14]

Explanation:

F=m×a

m=2kg

a=4m/s^2

F=2kg×4m/s^2

F=8N

6 0
3 years ago
A string is tied between two posts separated by 2.4 m. When the string is driven by an oscillator at frequency 567 Hz, 5 points
Alex787 [66]

Explanation:

The given data is as follows.

       Length (l) = 2.4 m

       Frequency (f) = 567 Hz

Formula to calculate the speed of a transverse wave is as follows.

                  f = \frac{5}{2l} \times v

Putting the gicven values into the above formula as follows.

                  f = \frac{5}{2l} \times v

                 567 Hz = \frac{5}{2 \times 2.4 m} \times v

                      v = 544.32 m/s

Thus, we can conclude that the speed (in m/s) of a transverse wave on this string is 544.32 m/s.

5 0
3 years ago
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