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ANEK [815]
3 years ago
11

When a light bulb is connected to a 4.5 V battery, a current of 0.12 A passes through the bulb filament. What is the resistance

of the filament? A) 440 Ω B) 28 Ω C) 9.3 Ω D) 1.4 Ω E) 38 Ω
Physics
1 answer:
Ksenya-84 [330]3 years ago
5 0

Answer:

Option (E) 38 ohm

Explanation:

Voltage, V = 4.5 V

Current, i = 0.12 A

Let r be the resistance of the filament of the bulb.

By use of Ohm's law

V = i x R

4.5 = 0.12 x R

R = 4.5 /  0.12 = 37.5 Ohm

By rounding off

R = 38 ohm

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Set local ground level to 700 ft, and record the inches of mercury.
pashok25 [27]

The altimeter reading is 29.17 from the Kollsman window is 29.17 in Hg

<h3>How to determine the altimeter reading?</h3>

The given parameters are:

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The formula to calculate the pressure altitude is:

Altitude = (29.92 – Altimeter reading) * 1,000 + Ground level

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Read more about pressure at:

brainly.com/question/26040104

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