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-BARSIC- [3]
3 years ago
14

While standing at the edge of the roof of a building, you throw a stone upward with an initial speed of 5.55 m/s. The stone subs

equently falls to the ground, which is14.7 m below the point where the stone leaves your hand. At what speed does the stone impact the ground? How much time is the stone in the air? Ignore air resistance and take g = 9.81 m/s2.
What is the Impact Speed:____m/s

What is the Elapsed Time:____s
Physics
1 answer:
dolphi86 [110]3 years ago
3 0
Let's solve first for the impact speed. The impact speed or velocity of any free-falling body follows the formula written below:

v = √2gy
where
y is the height of the free fall

Now, the length of y includes the distance it took for the upward motion, and the free falling motion that covers the maximum height plus the remaining distance of 14.7 ft. Let's compute first the maximum height reached:

Hmax = v₀²/2g, where v₀ is the initial velocity
Hmax = (5.55 m/s)²/2(9.81 m/s²) = 1.57 m
Thus,
y = 1.57 m + 14.7 m = 16.27 m
v = √2(9.81 m/s²)(16.27 m)
v = 17.87 m/s

For the second question, there are two sections of the total time. The first is the time for the upward motion:
t₁ = 2v₀/g = 2(5.55 m/s)/(9.81 m/s²) = 1.13 s
The second section is the time for the free fall:
t₂ = √2y/g = √2(16.27 m)/9.81 m/s² = 1.82 s
Thus, the total time is:
Time = 1.13 s + 1.82 s = 2.95 s
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3 years ago
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Explanation:

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A heavy piece of hanging sculpture is suspended by a 90 cm-long, 5.0 g steel wire. When the wind blows hard, the wire hums at it
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Answer: The mass of the sculpture is 11.8kg

Explanation:

Using the equation of fundamental frequency of a taut string.

f = (1/2L)*√(T/μ) .... (Eqn1)

Where

f= frequency in Hertz =80Hz

T = Tension in the string = Mg

M represent the mass of the substance (sculpture) =?

g= 9.8m/s^2

L= Length of the string=90cm=0.9m

μ= mass density = mass of string /Length of string

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L=0.9m

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Using (Eqn1)

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Square both sides

20736= T/0.0056

T= 116.12N

Recall that T =Mg

116.12= M * 9.8

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M= 11.8kg

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3 years ago
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