Answer:
force = 3000N
mass= 20 kg
now
F= ma
3000= 20×a
3000÷20=a
a=15
F= ma by newtons second law of motion
Answer:
18.22874999999973
I recommend you to round the nearest 1 d.p
Explanation:
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1.) Calculate the change in pH when 4.00 ml of 0.100 M HCl(aq) is added to 0.100 mL of a buffer solution that is 0.100 M in NH3 (aq) and 0.1000 M in NH4Cl(aq).
2.) Calculate the change in pH when 4.00 mL of 0.100 M in NaOH(aq) is added to the original buffer solution.
Answer:
The number of carbon atoms in the organic compound is 16.
Explanation:
The relative intensity of M + 1 peak (relative to M = 100) in organic compounds can be predicted by the following formula:
[M + 1] = (number of C x 1.07) ---------------------------------------------------- (1)
This formula can also be used to determine the number of carbon from the given intensity. But first, the intensity of [M + 1] relative to [M] = 100 needs to be determined, for which, consider the following calculations,
![[M+1]=(\frac{M+1}{M}) (100)](https://tex.z-dn.net/?f=%5BM%2B1%5D%3D%28%5Cfrac%7BM%2B1%7D%7BM%7D%29%20%28100%29)
![[M+1]=(\frac{7.022}{40.58}) (100)](https://tex.z-dn.net/?f=%5BM%2B1%5D%3D%28%5Cfrac%7B7.022%7D%7B40.58%7D%29%20%28100%29)
![[M+1]=17.30](https://tex.z-dn.net/?f=%5BM%2B1%5D%3D17.30)
Using equation 1 we get,
![number of C=\frac{[M+1]}{1.07}](https://tex.z-dn.net/?f=number%20of%20C%3D%5Cfrac%7B%5BM%2B1%5D%7D%7B1.07%7D)
or number of C = 16
The remaining value, 0.168, can be due to the isotopes of hydrogen and oxygen in the organic compound.
The units of light energy emitted by blackbody radiation is originally called as quanta. Black body radiation is a type of radiation within a boy in thermodynamic equilibrium. This is a theoretical body. In 1900, Planck proposed that light and other electromagnetic waves were emitted in discrete packets of energy which were called "quanta". This was the original unit used.
